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statuscvo [17]
2 years ago
12

A container with a volume 2.0 L is filled with a gas at a pressure of 1.5 atm. By decreasing the volume of the container to 1.0

L, what is the resulting pressure? Type in your answer using the correct number of significant figures. Remember to use the formula for Boyle's law: P1V1 = P2V2
Chemistry
1 answer:
belka [17]2 years ago
7 0

After reducing the starting volume, the gas has a resultant pressure of 3 atm.

Describe Boyle's Law.

Boyle's Law states that a gas's pressure is inversely proportionate to its volume at constant temperature:

P ∝ 1/V

The necessary equation for the posed question is:

P1V1 = P2V2, and

Initial pressure is P1 and is 1.5 atm.

Initial volume = 2 L for V1.

final pressure = P2 =?

Final volume = 1 L, or V2.

Using the aforementioned equation and all of these data, we obtain

P₂ = \frac{(1.5x2)}{1}= 3atm

Therefore, 3 atm of pressure is needed.

Learn more about Boyle's law here brainly.com/question/19491032

#SPJ10

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