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3 years ago

(view the image) explain your answer please

Chemistry

1 answer:

geniusboy [140]3 years ago

4 0

There is only one element with atomic mass 3 and it’s lithium and it only has 3 protons and 4 neutrons

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Pregunta borrada....

Julli [10]

Answer:

Cdiasuu alprguta bonrradse??

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3 years ago

Explain your thoughts on whether or not using solely IR is a good method to make positive IDs of chemicals.

Fed [463]

Answer:

No, IR should not soely be used to identify molecules

Explanation:

IR is a method that identifies the functional groups in a molecule by deducing the frequency of stretching and vibration of bonds. Each peculiar type of bond has a frequency for the vibration of each bond represented on the IR spectrum.

However, one method is never enough to identify a compound. A combination of methods must always be used to clear up ambiguities arising from overlapping IR frequencies. Also, interpretation of the nuanced peaks of the fingerprint region in IR spectra is quite challenging and only gives a fair idea of the functional groups present in the compound.

Therefore other methods such as NMR, UV-VISIBLE etc should also be involved in the identification of compounds.

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3 years ago

Which statement is part of the kinetic molecular theory?

Tcecarenko [31]

Answer:Option A

Explanation:

4 0

3 years ago

Read 2 more answers

What are the four elements that make up 96% of all living matter?

Wittaler [7]

I am pretty sure it is nitrogen, oxygen, carbon and hydrogen.

6 0

4 years ago

Read 2 more answers

Hellllppppp lons Worksheet

Iteru [2.4K]

The metals will lose electrons while the non metals will gain electrons in order to attain octet structure.

An ion can be cation (positively charged) or anion (negatively charged).

Cations attain octet structure (8) by losing electron(s) while anions become stable or attains octet structure (8) by gaining electron(s).

The remaining elements are completed as follows to attain octet structure;

Element--valence electron--electrons to gain--electrons to lose--ion formed

O ------------ 6 ---------------------- 2 ------------------------ none -------------- $O^{2-}$

Ca -------- 2 ----------------------- none ---------------------- 2 ------------------ $Ca^{2+}$

Br ----------- 7 --------------------- 1 ------------------------ none --------------- $Br^{-}$

S ------------ 6 ----------------------- 2 ------------------------ none --------------- $S^{2-}$

Cl ------------ 7 ----------------------- 1 ------------------------ none ---------------- $Cl^{-}$

K -------------- 1 ----------------------- none ----------------------- 1 ------------------ $K^{+}$

Mg ------------ 2 ---------------------- none ---------------------- 2 ---------------- $Mg^{2+}$

Be ------------- 2 ---------------------- none ---------------------- 2 ---------------- $Be^{2+}$

Learn more here: brainly.com/question/21089350

8 0

3 years ago