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Anna71 [15]
3 years ago
5

How many carbon atoms are there in 45g of carbon?

Chemistry
1 answer:
nevsk [136]3 years ago
3 0

Answer: 2.26x 10²⁴ atoms C

Explanation: To get the number of atoms,

First we convert mass of C to moles

45g C x 1mole C / 12 g C

= 3.75 moles C

Cancel g of C

Next convert moles of C to atoms using Avogadro's Number.

3.75 moles C x 6.022x10²³ atoms C / 1 mole C

Cancel out the units of moles C.

= 2.26x 10²⁴ atoms of C

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What is the next atomic orbital in the series 1s 2p 3s 3p
liq [111]

Answer:

s an example, the ground state configuration of the sodium atom is 1s22s22p63s1, as deduced from the Aufbau principle (see below). The first excited state is obtained by promoting a 3s electron to the 3p orbital, to obtain the 1s22s22p63p1 configuration, abbreviated as the 3p level.

Explanation:

3 0
3 years ago
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Earthquakes are vibrations of Earth's crust. Which of the following is used to
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A barometer is the answer
5 0
4 years ago
A) The lab tech called in sick today and you are called in to help prepare
jarptica [38.1K]
<h3>Answer:</h3>

318.405 g

<h3>Explanation:</h3>

We are given;

  • Volume of K₃PO₄ solution to be prepared as 750.0 mL or 0.75 L
  • Molarity of the solution to be prepared as 2.00 M

We are required to determine the mass of K₃PO₄ to be measured.

<h3>Step 1: Determine the number of moles of K₃PO₄</h3>

Molarity = Moles ÷ Volume

Rearranging the formula;

Number of moles = Molarity × Volume

Therefore;

Moles of K₃PO₄ = 2.00 M × 0.75 L

                          = 1.5 moles

<h3>Step 2: Determine the mass of K₃PO₄ to be measured</h3>

Mass = Number of moles × Molar mass

Molar mass of K₃PO₄ = 212.27 g/mol

Therefore;

Mass of K₃PO₄ = 1.5 moles × 212.27 g/mol

                        = 318.405 g

Therefore, the mass of K₃PO₄ that should be weighed is 318.405 g

7 0
3 years ago
At a certain temperature, the percent dissociation (ionization) of chlorous acid, HClO2, in a 1.43 M solution water is 8.0%. Cal
lakkis [162]

Answer:

Kₐ = 9.9 × 10⁻³

Explanation:

HClO₂ + H₂O ⇌ H₃O⁺ + ClO₂⁻

0.080 × 1.43 = 0.1144

So, at equilibrium,

[H₃O⁺] = [ClO₂⁻] = 0.1144

[HClO₂] = 1.43 – 0.1144 = 1.316

Kₐ = {[H₃O⁺][ClO₂⁻]}/[HClO₂];        Substitute values

Kₐ = (0.1144 × 0.1144)/1.316           Do the operations

Kₐ = 9.9 × 10⁻³

5 0
3 years ago
Can someone help me by giving me the formula of determining the amount of energy used in a reaction?
Vlada [557]
Q=mc(deltaT)
Q is the amount of energy which you are looking for
M is the mass which you can find
C is the specific heat of water which is 4.18 J/gC
DeltaT is the change in temperature which you can find.

To find the mass, first you must know that the density of water is 1g/mL, meaning that 200 mL has a mass of 200 g. This means that to find the total mass (m in the equation) all you need to do is add the mass of water and NaOH.

200 g + 2.535 g=202.535 g.

To find deltaT you would need to take the final temperature minus the initial temperature.

27.8C-24.2C=3.6C

Then these values can be substituted into the equation:

q=(202.635g)(4.18J/gC)(3.6C)
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Technically this should be rounded off to 1 significant figure (200 mL only had 1), but ignoring signficiant figure rules this should be correct. Also, sometimes other units like calories or kJ may be asked for, meaning that a conversion or alternate c value would be used.
5 0
4 years ago
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