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vivado [14]
2 years ago
11

Assume that the halting language

iddle" class="latex-formula"> is reducible to
some language B (H_T_M $\leq$ _m B). Is it possible that is decidable? Answer true/false and explain. Please help me this answer?
Mathematics
1 answer:
Volgvan2 years ago
4 0

H_TM is reduced to HALT_TM and as such, HALT_TM is undecidable.

<h3>How to Interpret Machine Language?</h3>

A language is referred to as Decidable or Recursive if there is a Turing machine that accepts and halts on every input string w. This tells us that every decidable language is Turing-Acceptable.

Now, we are told that the halting language is reducible to some language B. This means that it is an undecidability via reduction.

Now, Using the idea that “ If A is undecidable and reducible to B, then B is undecidable.” Suppose R decides HALT_TM, we will construct S to decide ATM .

S = “On input (M, B)

This means that H_TM is reduced to HALT_TM and as such, HALT_TM is undecidable.

Read more about machine language at; brainly.com/question/28026656

#SPJ1

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Carrie borrowed money from her sister Melissa. She has been paying her back $80 a month for the past 5 months. If this is 32% of
MrRa [10]

The money which is borrowed by Carrie to her sister Melissa which she has been paying her back $80 a month is $1250.

<h3>What is percentage of a number?</h3>

Percentage of a number is the part of the whole number which is expressed in the fraction of hundredth. It is represented with "%" symbol.

Carrie borrowed money from her sister, whose name is Melissa. She has been paying her back $80 a month for the past 5 months. Thus, the total amount she has returned is,

x=$80×5

x=$400

Now, the $400 is 32% of the money that she borrowed. Thus, the amount of money which she borrowed is,

\text{Money}=\dfrac{400}{32}\times100\\\text{Money}=1250

Thus, the money which is borrowed by Carrie to her sister Melissa which she has been paying her back $80 a month is $1250.

Learn more about the percentage here;

brainly.com/question/2085058

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4 0
2 years ago
Reflectional symmetry is the quality a design has if it maintains all
stiks02 [169]
I think the answer is b
8 0
3 years ago
What are matching partial products?
motikmotik
Just say partial products that relate to one another
5 0
3 years ago
Write the equation of the line (in slope-intercept form) that passes through the points (-5.6) and (-6,4)
I am Lyosha [343]

Answer:

Step-by-step explanation:

(4 - 6)/(-6+5)= -2/-1= 2

y - 6 = 2(x + 5)

y - 6 = 2x + 10

y = 2x + 16

7 0
4 years ago
Help with number 6 please. thank you.​
Gwar [14]

Answer:

See Below.

Step-by-step explanation:

We are given that:

\displaystyle \frac{dT}{dt} = -k(T - T_0)

And we want to show that:

\displaystyle T = T_0+Ae^{-kt}

From the original equation, divide both sides by (<em>T</em> - <em>T₀</em>) and multiply both sides by dt. Hence:

\displaystyle \frac{dT}{T-T_0}= -k\, dt

Take the integral of both sides:

\displaystyle \int \frac{dT}{T- T_0} = \int -k \, dt

Integrate. For the left integral, we can use u-substitution. Note that <em>T₀</em> is simply a constant. Hence:

\displaystyle \ln\left|T - T_0\right| = -kt+C

Raise both sides to e:

\displaystyle e^{\ln\left|T-T_0\right|} = e^{-kt+C}

Simplify:

\displaystyle \begin{aligned} \left| T- T_0\right| &= e^{-kt} \cdot e^C \\ \\ &= e^C\left(e^{-kt}\right) \\ \\ &=Ae^{-kt} & \text{Let $e^C = A$}\end{aligned}

Since the temperature <em>T</em> will always be greater than or equal to the surrounding medium <em>T₀</em>, we can remove the absolute value. Hence:

<em />\left(T - T_0\right) = Ae^{-kt}<em />

Therefore:

\displaystyle T = T_0+Ae^{-kt}

5 0
3 years ago
Read 2 more answers
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