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2 years ago

14

PLEASE HELP! I WILL MAKE YOU BRAINLIST!

1 answer:

Shkiper50 [21]2 years ago

7 0

Answer: A.

Step-by-step explanation: yes

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Given the following functions f(x) and g(x), solve f over g (−5) and select the correct answer below:

ahrayia [7]

Plug -5 into both of them and divide:

$\sf\dfrac{2x-20}{x-1}$

$\sf\dfrac{2(-5)-20}{-5-1}$

Simplify:

$\sf\dfrac{-10-20}{-6}$

$\sf\dfrac{-30}{-6}$

$\boxed{\sf 5}$

7 0

2 years ago

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I NEED HELP ASAP PLEASE!!!!!

valkas [14]

Answer:

the answer is 83 degrees

Step-by-step explanation:

most angles that connect diagonally are vertically opposite angles. hope it helps have a great day and can i get brainliest

7 0

2 years ago

The cost C (in millions of dollars) for the federal government to seize p% of an illegal drug as it enters the country is given

erik [133]

Answer:

b for me hehe ok

Step-by-step explanation:

Explanation

3 0

2 years ago

Use the power series for 1 1−x to find a power series representation of f(x) = ln(1−x). What is the radius of convergence? (Note

Viktor [21]

a. Recall that

$\displaystyle\int\frac{\mathrm dx}{1-x}=-\ln|1-x|+C$

For $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{n=0}^\infty x^n$

By integrating both sides, we get

$\displaystyle-\ln(1-x)=C+\sum_{n=0}^\infty\frac{x^{n+1}}{n+1}$

If $x=0$ , then

$\displaystyle-\ln1=C+\sum_{n=0}^\infty\frac{0^{n+1}}{n+1}\implies 0=C+0\implies C=0$

so that

$\displaystyle\ln(1-x)=-\sum_{n=0}^\infty\frac{x^{n+1}}{n+1}$

We can shift the index to simplify the sum slightly.

$\displaystyle\ln(1-x)=-\sum_{n=1}^\infty\frac{x^n}n$

b. The power series for $x\ln(1-x)$ can be obtained simply by multiplying both sides of the series above by $x$ .

$\displaystyle x\ln(1-x)=-\sum_{n=1}^\infty\frac{x^{n+1}}n$

c. We have

$\ln2=-\dfrac\ln12=-\ln\left(1-\dfrac12\right)$

$\displaystyle\implies\ln2=\sum_{n=1}^\infty\frac1{n2^n}$

4 0

3 years ago

Which relationship has a zero slope

vesna_86 [32]

Answer:

The first table.

Step-by-step explanation:

A slope of 0 means that as x increases, y stays the same. In the first table, all of our y-values are 2; this means that y stays constant.

To prove it, we use our formula for slope:

$m=\frac{y_2-y_1}{x_2-x_1}$

The slope of the line between the first two points is

(2-2)/(-3--1) = 0/-2 = 0

The slope of the line between the second pair of points is

(2-2)/(-1-1) = 0/-2 = 0

The slope of the line between the next pair of points is

(2-2)/(1-3) = 0/-2 = 0

Since the slope between each pair of points is 0, the slope of the entire line is 0.

4 0

2 years ago

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