Find the integrals: ∫1÷(x(㏑x-π)^4)dx

1 answer:

Maru [420]2 years ago

4 0

Answer:

$C-\frac{1}{3(lnx- \pi)^3}.$

Step-by-step explanation:

$\int\ {\frac{1}{x(lnx- \pi)^4} } \, dx=\int\ {\frac{d(lnx- \pi)}{(lnx- \pi)^4}} \, dx=-\frac{1}{3(lnx- \pi)^3} +C.$

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