Question

Find the consecutive positive odd integers whose product is 99​

Answer 1

Answer:

9 and 11

Step-by-step explanation:

So let's say that the first integer is x.

That means that the second integer is x+2, since it us the next odd number.

This problem can be easily solved with our mind the answer is 9 and 11, but I'll show you the steps to slove this.

We make an equation using these two numbers:

$(x)*(x+2)=99$

Now all we gotta do is solve for x:

$x^2 +2x = 99\\x^2+2x-99=0$

Now we use either splitting the middle term or quadratic formula:

$x^2+11x-9x+99=0\\x(x+11)-9(x+11)=0\\(x+11)(x-9)=0$

Now we split each terma and solve for x:

$(x-9)=0\\x=9\\(x+11)=0\\x=-11$

Now the question states positive so we can rule out x = -11.

Now we have the first integer x = 9,

the second integer is x+2 = 9+2 =11

So the two consecutive positive odd integers are 9 and 11