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3 years ago

1 2/3 times 3 2/3 greater than 3 2/3

Mathematics

1 answer:

jek_recluse [69]3 years ago

3 0

Yes, yes it is :)
your welcome

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-9 is less than or equal to x and 7 is greater than or equal to x

const2013 [10]

Plot a point at "-9" and the other at "7". Both dots will be shaded in.

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3 years ago

How do you solve this?

Murrr4er [49]

Answer: I thought you already asked this question.

Step-by-step explanation:

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1 year ago

132=-6+3(1-5p) solve the equation

photoshop1234 [79]

Answer:

p=-9

Step-by-step explanation:

132=-6+3 (1-5p)

-6+3 (1-5p)=132

-6+3 (1-5p)+6=132+6

3(1-5p)=138

3(1-5p)/3=138/3

1-5p=46

1-5p-1=46-1

-5p=45

p=-9

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3 years ago

Read 2 more answers

Which equation is the inverse of y = 9x2 - 4?

m_a_m_a [10]

Answer:

The inverse will be:

$y' = \frac{\sqrt{x+4}}{3}$

Step-by-step explanation:

In order to find the inverse of the equation, we do a variable change, since we are finding the inverse, :

$f(x) = 9x^{2} - 4$

$y = 9x^{2} - 4$

$x = 9y' ^{2} - 4$

Now solve for y'.

First add 4 in both sides of the equation and change to the left y'.

$x + 4= 9y'^{2} - 4+4$

$9y'^{2}$ = x + 4

Second divide by 9

$9y'^{2}$ /9 = (x + 4)/9

$y'^{2}$ = (x + 4)/9

Now you will have to clear y, with the square root.

$[tex]y'^{\frac{2}{2}} = \sqrt{x + 4} / \sqrt{9}$ [/tex] =

Simplifying terms

$y' = \frac{\sqrt{x+4}}{3}$

$f^{-1}(x) = \frac{\sqrt{x+4}}{3}$

You can check the answer by doing the evaluation of the following equation:

(f o $f^{-1}$ ) (x)

substitute the equation for y' or inverse function $f^{-1}$

f( $\frac{\sqrt{x+4} }{3}$ )

Now substitue the value into f(x)

You will have

$= 9(\frac{\sqrt{x+4} }{3}} )^{2} - 4\\\\Solving\\\\9(\frac{{x+4} }{9}} ) - 4$

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3 years ago

You flip a coin 12 times. What is the probability of getting only one tails in all 12 tries?

tigry1 [53]

Answer: Aproxamatly 18.999999999999999

Step-by-step explanation:

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2 years ago