The molar mass of the acid, given the data is 625 g/mole
<h3>What is equivalence point?</h3>
This is a point is a titration reaction where the amount of the acid added is enough to neutralize the base
This simply implies that the number of mole of the acid used is equal to the number of mole of the base.
<h3>How to determine the mole of the base</h3>
- Volume of base (NaOH) = 20 mL = 20 / 1000 = 0.02 L
- Molarity of base (NaOH) = 0.1 M
- Mole of base (NaOH) = ?
Mole = molarity × volume
Mole of base (NaOH) = 0.1 × 0.02
Mole of base (NaOH) = 0.002 mole
<h3>How to determine the molar mass of the acid</h3>
- Mole of base (NaOH) = 0.002 mole
- Mole of acid = Mole of base (NaOH) = 0.002 mole
- Mass of acid = 1.25 g
- Molar mass of acid =?
Molar mass = mass / mole
Molar mass of acid = 1.25 / 0.002
Molar mass of acid = 625 g/mole
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