Question

Using the Bohr model, determine the lowest possible energy, in joules, for the electron in the Li2+ ion.

Answer 1

Answer: E = - 19.611×$10^{-18}$ J

Explanation: The lowest possible energy can be calculated using the formula:

$E_{n} = - Z^{2}.\frac{k}{n^{2}}$

where:

Z is atomic number of the atom;

k is a constant which contains other constants and is 2.179×$10^{-18}$ J

n is a layer;

For the lowest possible, n=1.

Atom of Lithium has atomic number of Z=3

Substituing:

$E_{1} = - 3^{2}.\frac{2.179.10^{-18}}{1}$

$E_{1} =$ $-19.611.10^{-18}$ J

The energy for the electron in the $Li^{+2}$ ion is - 19.611 joules