Question

How much 0.2M HCl can be made from 5.0mL of a 12.0M HClSolution?

Answer 1

Answer: The volume of 0.10 M NaOH required to neutralize 30 ml of 0.10 M HCl is, 30 ml.

Explanation:

According to the dilution law,

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of stock $HCl$ solution = 12.0 M

$V_1$ = volume of stock $HCl$solution = 5.0 ml

$M_2$ = molarity of dilute $HCl$ solution = 0.2 M

$V_2$ = volume of  dilute $HCl$  solution = ?

Putting in the values we get:

$(12.0M)\times 5.0=0.2\times V_2$

$V_2=300ml$

Therefore, 300 ml of 0.2M HCl can be made from 5.0mL of a 12.0M $Hcl$ solution.