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nata0808 [166]
2 years ago
13

Solve the system of equations. y+4z=0 4x+y-2z=2 -3x-3z=-9

Mathematics
2 answers:
vazorg [7]2 years ago
7 0

Answer:

  • x = 7/3
  • y = - 8/3
  • z = 2/3

Step-by-step explanation:

y + 4z = 0

4x + y - 2z = 2

____________ -

- 4x + 6z = - 2

- 4x + 6z = - 2 → times 3 → - 12x + 18z = - 6

- 3x - 3z = - 9 → times 4 → - 12x - 12z = - 36

- 12x + 18z = - 16

- 12x - 12z = - 36

______________ -

30z = 20

z = 20/30

z = 2/3

y + 4(2/3) = 0

y + 8/3 = 0

y = - 8/3

- 3x - 3z = - 9

- 3x - 3(2/3) = - 9

- 3x - 6/3 = - 9

- 3x - 2 = - 9

- 3x = - 9 + 2

- 3x = - 7

x = - 7/- 3

x = 7/3

antoniya [11.8K]2 years ago
3 0

Step-by-step explanation:

y+4z=0

4x+y-2z=2

-3x-3z=-9

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Express the product of (1/5x + 1) and (1/6x + 5/4) as a trinomial in simplest form
Greeley [361]
(\frac{1}{5}x+1)(\frac{1}{6}x+\frac{5}{4})

Use distributive property to remove the parentheses:

(a+b)(c+d)=ac+ad+bc+bd\begin{gathered} =\frac{1}{5}x*\frac{1}{6}x+\frac{1}{5}x*\frac{5}{4}+1*\frac{1}{6}x+1*\frac{5}{4} \\  \\ Multiplication\text{ }of\text{ }fractions: \\ \frac{a}{b}*\frac{c}{d}=\frac{a*c}{b*d} \\  \\ =\frac{1}{30}x^2+\frac{5}{20}x+\frac{1}{6}x+\frac{5}{4} \\  \\ =\frac{1}{30}x^2+\frac{1}{4}x+\frac{1}{6}x+\frac{5}{4} \\  \\ Addition\text{ }of\text{ }fractions: \\ \frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd} \\  \\ =\frac{1}{30}x^2+(\frac{6x+4x}{24})+\frac{5}{4} \\  \\ =\frac{1}{30}x^2+\frac{10}{24}x+\frac{5}{4} \\  \\ Simplify: \\ =\frac{1}{30}x^2+\frac{5}{12}x+\frac{5}{4} \end{gathered}Then, the product in the simplest form is:\frac{1}{30}x^2+\frac{5}{12}x+\frac{5}{4}

8 0
1 year ago
There are 7 people on a cycling team. Their coach mush pick two of them to be Co - Captain. How many different pairs can the cou
garik1379 [7]
21, because 7 choose 2 = 21
4 0
3 years ago
Hello can someone try and help me
lyudmila [28]

Answer:

f(x)=-4x+/4

let y=f(x)

y=-4x+4

interchange the role of x & y

x=-4y+4

x-4=-4y

(x-4)/-4=y

y=-(x-4)/4

f-¹(x)=-(x-4)/4

yeah you are right

4 0
3 years ago
Please help me with these. <br> Thanks
DIA [1.3K]
5.

f(K) = D^3 => f(25) = 125 => 25 * t = 125 ( because K is directly proportional with D^3 )=> t = 125 / 25 => t = 5 => f(25) = 25 * 5 => K * 5 = D^3 ;

6. 

f(L) = F^3 => f(2) =3^3 =>f(2) = 27 => 2 / t =27 => t = 2 / 27 => t = 0.074 => f(2) = 2 / 0.074 => K / 0.074 = F^3 ;


6 0
4 years ago
9th grade math help me please and thank you sosomuch
Varvara68 [4.7K]

Answer:

The system is consistent; it has one solution ⇒ D

Step-by-step explanation:

A consistent system of equations has at least one solution

  • The consistent independent system has exactly 1 solution
  • The consistent dependent system has infinitely many solutions

An inconsistent system has no solution

In the system of equations ax + by = c and dx + ey = f, if

  1. a = d, b = e, and c = f, then the system is consistent dependent and has infinitely many solutions
  2. a = d, b = e, and c ≠ f, then the system is inconsistent and has no solution
  3. a ≠ d, and/or b ≠ e, and/or c ≠ f, then the system is consistent independent and has exactly one solution

In the given system of equations

∵ -2y + 2x = 3 ⇒ (1)

∵ -5y + 5x = 12 ⇒ (2)

→ By comparing equations (1) and (2)

∵ -2 ≠ -5

∵ 2 ≠ 5

∵ 3 ≠ 12

→ By using the 3rd rule above

∴ The system is consistent independent and has exactly one solution

∴ The system is consistent; it has one solution

7 0
3 years ago
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