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1 year ago

Solve the system of equations. y+4z=0 4x+y-2z=2 -3x-3z=-9

Mathematics

2 answers:

vazorg [7]1 year ago

7 0

Answer:

x = 7/3
y = - 8/3
z = 2/3

Step-by-step explanation:

y + 4z = 0

4x + y - 2z = 2

____________ -

- 4x + 6z = - 2

- 4x + 6z = - 2 → times 3 → - 12x + 18z = - 6

- 3x - 3z = - 9 → times 4 → - 12x - 12z = - 36

- 12x + 18z = - 16

- 12x - 12z = - 36

______________ -

30z = 20

z = 20/30

z = 2/3

y + 4(2/3) = 0

y + 8/3 = 0

y = - 8/3

- 3x - 3z = - 9

- 3x - 3(2/3) = - 9

- 3x - 6/3 = - 9

- 3x - 2 = - 9

- 3x = - 9 + 2

- 3x = - 7

x = - 7/- 3

x = 7/3

antoniya [11.8K]1 year ago

3 0

Step-by-step explanation:

y+4z=0

4x+y-2z=2

-3x-3z=-9

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The first step would be to put in the fact that the sequence starts at 8

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The blank is going to include the difference between each number in the sequence; that is, how much it’s increasing by. To find it, get the difference between any two (consecutive!) terms.

10 - 8

12 - 10

14 - 12

All of these are equal to 2. Therefore, our gap is going to include “2”

y = 8 + 2x

To find the hundredth term, simply plug in 99 for x (the reason being that plugging in 0 for x gives us 8, but this is considered the first term. Therefore, x - 1 is the actual term)

y = 8 + 2(99)

y = 8 + 198

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3 years ago

Let T:R²->R² be a linear transformation ,and assume that T (1,2)=(-1,1) and T(1,-1)=(2,3)

zavuch27 [327]

Answer:

(-4,-1)

Step-by-step explanation:

We are given T(1,2)=(-1,1) and T(1,-1)=(2,3) and T is a linear transformation.

This implies for scalars a and b that

T(a(1,2)+b(-1,1))=aT(1,2)+bT(-1,1)

T((a,2a)+(-b,b))=a(-1,1)+b(2,3)

T((a-b,2a+b))=(-a,a)+(2b,3b)

T((a-b,2a+b))=(-a+2b,a+3b)

This means we should be able to solve the system below to find a and b for T(3,3):

a-b=3 and 2a+b=3

Add equations to eliminate b and solve for a:

3a=6

Divide 3 on both sides:

a=2

If a-b=3 and a=2, then b=-1.

Plug in a=2, b=-1:

T((a-b,2a+b))=(-a+2b,a+3b)

T((2--1,2×2+-1)=(-2+2×-1,2+3×-1)

T(3,3)=(-4,-1).

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2 years ago