Question

Write a quadratic function F whose zeros are 12 and 1

Answer 1

Answer:

$f(x) = (x-12)(x-1)$

Step-by-step explanation:

So when you have a quadratic equation it can usually be expressed as: $a(x-b)(x-c)$ where b and x are the roots of the equation. Since it's just asking for a function whose zeroes are 12 and 1, I'm assuming it doesn't care about the stretch/compression (value of a determines that), so I'll just assume a=1. if 12 and 1 are zeroes, that means it makes one of the factors equal to 0 because is x-b = 0 then no matter the value of x-c the value of y is 0 because 0 * (x-c) will be 0. So the equation becomes $f(x) = (x-12)(x-1)$ plugging in 12 or 1 as x will make one of the factors 0 thus making f(x) equal to 0