Answer:
Step-by-step explanation:
Cardinality of a set is defined as number of element in a set. It is represented as n(X) where X is any set.
a) Given the set A =(x l x € N and 20.< x<27). According to the set, the set contains the values of natural numbers between 20 and 27. The values are 21, 22, 23, 24, 25 and 26
A = (21, 22, 23, 24, 25, 26)
According to the set A, it can be seen that there are 6 elements in the set, <em>this means n(A) = 6.</em>
b) Given B=(x | xeN and x+1=x)
Since natural numbers starts from 1, the first element in the set is 2 i.e 1+1
The elements of the set B = (2, 3, 4, 4...)
<em>The number of whole number in the set is therefore infinite. </em>
c) For the set C={x l xe N and (x- 1)(x - 9) = 0)
We need to get the root of the equation (x- 1)(x - 9) = 0
x-1 = 0 and x-9 = 0
x = 1 and x = 9
Hence the element C = (1,9)
<em>The number of whole number in the set is n(C) = 2</em>
d) D={xlx E N, H X 5 100, and x is divisible by both 5 and 8)
Given the value of x between 5 and 100, the values of x divisible by 5 = (10, 15, 20, 25, 30, 35, 40, 45, 50 , 55, 60 , 65, 70, 75, 80 85, 90, 95)
values of x divisible by 8 = (16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96)
<em>The total number of elements in both set = 29 i.e n(D) = 29 </em>
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![y=4(\sqrt[3]{\frac{95}{4}})^{x}](https://tex.z-dn.net/?f=y%3D4%28%5Csqrt%5B3%5D%7B%5Cfrac%7B95%7D%7B4%7D%7D%29%5E%7Bx%7D)
