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Delvig [45]
3 years ago
13

In EFGH find the measure of GFH !!!! PLEASE HELP!!!!

Mathematics
1 answer:
stich3 [128]3 years ago
6 0

Answer:

C

Step-by-step explanation:

Since EF and GH are parallel lines then

∠EGF = ∠GFH = 60° ( Alternate angles )

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Korolek [52]
Hey there! 

In order to find out the answer to this question, we can distribute 

-30 = 2(x - 97) \\ \\ \\ 2(x) = 2x \\ \\ 2(97) = 197

Flip your problem around! 

2x - 194 = -30

Add by 194 on each of your sides 

Like:  2x - 194 + 194 \\ \\ \\ -30 + 194

Cancel out: -194 + 194  because they would give you the outcome of 0

Keep: -30 + 194 [/tex] because that'll give you: [tex]164

Your problem becomes: 2x = 164

Now, we have to divide by 2 on each of the sides

Like: \frac{2x}{2}  =  \frac{164}{2}

Cancel: \frac{2x}{2} because it will give you a outcome of 1

Keep: \frac{164}{2} because this will give you your answer

Answer: x = 82

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)
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3 years ago
Help needed ASAP will give you BRAINLIEST and 5 stars rate
iVinArrow [24]
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Which of the following best describes the graph of the polynomial function below?
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Answer:

A. The graph has two zeroes.

Step-by-step explanation:

A <em>zero of a polynomial</em> is a value of x that makes the polynomial equal to zero.

In other words, it is <em>an x-intercept</em>.

The graph crosses the x-axis twice, so there are two zeroes.

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If the length of side a is 12 centimeters, m∠B = 36°, and m∠C = 75°, what is the length of side b? Round your response to two de
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You know the measure of the exterior angle which forms a linear pair with the vertex angle. Describe two ways you can find measu
aev [14]

Answer:

Step-by-step explanation:

A linear pair are two given angles whose sum is equal to 180^{o}.

Let the exterior angle be represented by x^{o}, and the three interior angles of the triangle be represented by a^{o}, b^{o} and c^{o}.

Assume that the vertex angle c^{o} is the linear pair to the exterior angle x^{o}.

i.e            x^{o} + c^{o} = 180^{o}  (sum of angles on a straight line)

Thus,

i. a^{o} +  b^{o} = x^{o}  (sum of two opposite interior angles is equal to an exterior angle)

⇒ a^{o}  = x^{o} - b^{o}

Also,

b^{o}  = x^{o} - a^{o}

But,

a^{o} + b^{o} + c^{o} = 180^{o}   (sum of angles in a triangle)

⇒ c^{o} = 180^{o} - (a^{o} +  b^{o})

and

a^{o} + b^{o} = 180^{o} - c^{o}

ii. a^{o} + b^{o} + c^{o} = 180^{o}   (sum of angles in a triangle)

a^{o} = 180^{o} - (b^{o} + c^{o})

Also,

a^{o} +  b^{o} = x^{o}

⇒ b^{o} = x^{o} - a^{o}

c^{o} = 180^{o} - x^{o}

8 0
3 years ago
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