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3 years ago

In EFGH find the measure of GFH !!!! PLEASE HELP!!!!

Mathematics

1 answer:

stich3 [128]3 years ago

6 0

Answer:

Step-by-step explanation:

Since EF and GH are parallel lines then

∠EGF = ∠GFH = 60° ( Alternate angles )

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Solve for s. 8 - 4s = s + 13

Andrej [43]

Answer:

s= -1

Step-by-step explanation:

5 0

3 years ago

Pls help !! Solve and CHECK. 1 / 4 ( p - 7) = 1/6 ( p - 3)

victus00 [196]

Answer:

the answer would be p= 15

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Rotation 180 about the origin E(2,-2), J(1,2), R(3,3), S(5,2)

hammer [34]

E' (-2, 2) , J'(-1, -2) , R'(-3,-3) , S'(-5, -2)

6 0

3 years ago

Which are the solutions of the quadratic equation? x2 = –5x – 3 –5, 0 StartFraction negative 5 minus StartRoot 13 EndRoot Over 2

boyakko [2]

Given:

The quadratic equation is $x^{2}=-5 x-3$

We need to determine the solutions of the quadratic equation.

Solution:

Let us solve the equation to determine the value of x.

Adding both sides of the equation by 5x and 3, we get;

$x^{2}+5 x+3=0$

The solution of the equation can be determined using quadratic formula.

Thus, we get;

$x=\frac{-5 \pm \sqrt{5^{2}-4 \cdot 1 \cdot 3}}{2 \cdot 1}$

$x=\frac{-5 \pm \sqrt{25-12}}{2 }$

$x=\frac{-5 \pm \sqrt{13}}{2 }$

Thus, the two roots of the equation are $x=\frac{-5 + \sqrt{13}}{2 }$ and $x=\frac{-5- \sqrt{13}}{2 }$

Hence, the solutions of the equation are $x=\frac{-5 + \sqrt{13}}{2 }$ and $x=\frac{-5- \sqrt{13}}{2 }$

6 0

3 years ago

Read 2 more answers

Wes works at a science lab that conducts experiments on bacteria. The population of the bacteria multiplies at a constant rate,

Dmitry [639]

Answer:

Correct answer: at 2 p.m. the population was 10,000

at 3 p.m. the population was 50,000

Step-by-step explanation:

At 1 p.m. population was 2,000

At 2 p.m. or after first hour, the population of bacteria increases

in this way 2,000 · k

At 3 p.m. or after second hour, the population of bacteria increases

2,000 · k²

At 4 p.m. or after third hour, the population of bacteria increases 2,000 · k³

2,000 · k³ = 250,000 => k³ = 250,000 / 2,000 = 125

k = ∛125 = 5 => k = 5

At 2 p.m. or after first hour, the population of bacteria was 2,000 · 5 = 10,000

At 3 p.m. or after second hour, the population of bacteria was 2,000 · 5² =

= 2,000 · 25 = 50,000

God is with you!!!

6 0

3 years ago