If you copied the "n 3" part, it's very likely that your job was to create a pattern with either the rule n^3 or n*3.
In the case of the former, we can start with the initial number of 1 and increase by 1.
In that way, using the rule n^3 would create this pattern of numbers: 1, 8, 27, 64, and so on. Or stated in another way 1*1*1, 2*2*2, 3*3*3, 4*4*4 ...
In the case of the latter, we can start with the initial number of 1 and increase it by 1.
In this way, using the rule of n*3 would create this pattern of numbers: 3, 6, 9, 12, 15, 18 and o son. Or stated in another way 1*3, 2*3, 3*3, 4*3, 5*3 ...
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1. Yes
2. No
3. 46.6 (recurring)
5. 22'
Sorry this is all I can do. Hope this helps :)
The answer you are looking for is $70
hope that helps!!!
Answer:
When x = 4, (4, 0)
When y = 4, (6, 4)
Step-by-step explanation:
To find the ordered-pair solution when x = 4, plug 4 into the x of the equation.
y = 2x - 8
y = 2(4) - 8
y = 8 - 8
y = 0
This produces the ordered pair (4, 0).
To find the ordered-pair solution when y = 4, plug 4 into the y of the equation.
y = 2x - 8
4 = 2x - 8
12 = 2x
6 = x
x = 6
This produces the ordered pair (6, 4).
