Subtract 6x 2 −7x−2 from 6x^{2}-2x+6
1 answer:
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Since the centre is at the origin, (h, k) = (0, 0)
Hence, we can substitute h and k as 0 respectively.
General form:
Now, we know that (0, 4) lies on the circle. Thus, the radius must be 4 units.
So, our circle becomes:
Now, substitute (2, 6) to see if it lies on the circle.
Hence, it doesn't lie on the circle.
Hence, we can substitute h and k as 0 respectively.
General form:
Now, we know that (0, 4) lies on the circle. Thus, the radius must be 4 units.
So, our circle becomes:
Now, substitute (2, 6) to see if it lies on the circle.
Hence, it doesn't lie on the circle.