Consider the length of diagonal is 8.5 cm instead of 8.5 m because length of perpendiculars are in cm.
Given:
Length of the diagonal of a quadrilateral = 8.5 cm
Lengths of the perpendiculars dropped on it from the remaining opposite vertices are 3.5 cm and 4.5 cm.
To find:
The area of the quadrilateral.
Solution:
Diagonal divides the quadrilateral in 2 triangles. If diagonal is the base of both triangles then the lengths of the perpendiculars dropped on it from the remaining opposite vertices are heights of those triangles.
According to the question,
Triangle 1 : Base = 8.5 cm and Height = 3.5 cm
Triangle 2 : Base = 8.5 cm and Height = 4.5 cm
Area of a triangle is

Using this formula, we get


and


Now, area of the quadrilateral is



Therefore, the area of the quadrilateral is 34 cm².
Answer:
a) 2nd
b) 4.8
c) 4
Step-by-step explanation:
Mode is the highest frequency.
"Away" has highest frequency in the second quarter
Mean = sum/n
Sum of Home goals:
5+4+8+9 = 26
Sum of Away goals:
2+9+7+4 = 22
Total goals = 26+22 = 48
Average = 48/10 = 4.8
No. of home goals - No. of away goals
26 - 22 = 4
Answer:
A
Step-by-step explanation:
A is a triangular prism