There are three steps:<span>
1.)Rearrange the equation so "y" is on the left and everything else on the right.
2.)Plot the "y=" line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>)
<span>
3.)Shade above the line for a "greater than" (y> or y≥) or below the line for a "less than" (y< or y≤).</span></span>
Answer:
C
Step-by-step explanation:
Answer:
17 i think
Step-by-step explanation:
Answer:
see the attachment
Step-by-step explanation:
We assume that the question is interested in the probability that a randomly chosen class is a Friday class with a lab experiment (2/15). That is somewhat different from the probability that a lab experiment is conducted on a Friday (2/3).
Based on our assumption, we want to create a simulation that includes a 1/5 chance of the day being a Friday, along with a 2/3 chance that the class has a lab experiment on whatever day it is.
That simulation can consist of choosing 1 of 5 differently-colored marbles, and rolling a 6-sided die with 2/3 of the numbers being designated as representing a lab-experiment day. (The marble must be replaced and the marbles stirred for the next trial.) For our purpose, we can designate the yellow marble as "Friday", and numbers greater than 2 as "lab-experiment".
The simulation of 70 different choices of a random class is shown in the attachment.
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<em>Comment on the question</em>
IMO, the use of <em>70 trials</em> is coincidentally the same number as the first <em>70 days</em> of school. The calendar is deterministic, so there will be exactly 14 Fridays in that period. If, in 70 draws, you get 16 yellow marbles, you cannot say, "the probability of a Friday is 16/70." You need to be very careful to properly state the question you're trying to answer.
The answer is B)x+y=y+x.
This is just changing the order of the numbers to get the same equation....\
So for example if I have 2+7 and I use the property of addition It would give me 2+7=7+2.
Pls mark brainliest if this helped!