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1 year ago

Please helpppppppppp thanks!

Mathematics

2 answers:

Nookie1986 [14]1 year ago

7 0

Answer:

$a < 0$ False

$|a| > 0$ True

$|a|=0$ False

________________________________________________

a is on the right side of 0,

which means a is positive.

The absolute value is the distance to zero (always positive)

Which means the absolute value of a is also positive.

$a < 0$ is wrong because a is positive

$|a| > 0$ is correct because a is larger than 0

$|a|=0$ is wrong because $a$ ≠ $0$

________________________________________________

Hope this helps :)

Simora [160]1 year ago

4 0

Answer:

First one is false. (You are correct)
Second is true. (a will be greater than 0)
Third is also false. (a can't be equal to 0)

Hope it helps!!

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Which is the equation of a circle whose center is at the origin and that passes through the point (3, 5)?

xxTIMURxx [149]

Answer:

x² + y² = 34

Formula:

(x - h)² + (y - k)² = r² where (h, k) is the center

Here find the radius using distance formula: → origin : (0, 0)

√(x2-x1)²+(y2-y1)²

√(3-0)²+(5-0)²

√9+25

√34

Thus the equation of circle:

(x - 0)² + (y - 0)² = (√34)²

(x - 0)² + (y - 0)² = 34

x² + y² = 34

7 0

2 years ago

Read 2 more answers

– 42 – 54 + 96 = what is the answer

mart [117]

Answer:

Answer:the answer is zero 

Answer:the answer is zero Step-by-step explanation:

Answer:the answer is zero Step-by-step explanation:when we add -42 and -54 the answer we get is -96. -96and +96 cut each other and then the answer is zero 

 $- 42 - 54 + 96 = 0$ 

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1 year ago

17. Your goal is to save at least $360.00 over the next 6 weeks. How much money must you save each week in order to meet that go

OLga [1]

<h2>Answer </h2>

D. 6x>_360; x>_60

<h2>Explanation</h2>

Let $x$ be amount you will save each weeks

Since we know that you are saving over a period of 6 weeks, you will save $6x$ .

We also now that your goal is to save at least $360.00 over the period of 6 weeks, so saving more than $360.00 will be very desirable, but the goal is to save $360.00. We can rephrase this as: You need to save $360.00 or more; we can say the same using the inequality symbol $\geq$ (greater on equal than)

Now we can combine our tow parts using the inequality symbol:

$6x\geq 360$

To simplify divide both sides by 6:

$\frac{6}{6} x\geq \frac{360}{6}$

$x\geq 60$

You need to save at least $60 per week, so the correct answer is D. 6x>_360; x>_60

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3 years ago

Graph the function and analyze it for domain, range, continuity, increasing or decreaseing behavior, symmetry, boundedness, extr

Sunny_sXe [5.5K]

Answer:

$f(x) = 3 \cdot 0.2^x$

Step-by-step explanation:

$f(x) = 3 \cdot 0.2^x$

Domain of f: "What values of x can we plug into this equation?" This makes sense for all real numbers so the domain is $\mathbb{R}$

Range of f: "What values of f(x) can we get out of the function?" From the graph we see we can get any real number greater than 0 out of the function by choosing a suitable x-value in the domain. The range is therefore $(0, \infty)$ .

Continuity: Since the graph is one, unbroken curve (i.e. a curve that can be drawn in one movement without taking your pen off the paper). We see that "roughly speaking" the function is continuous.

Increasing or decreasing behaviour: For all x in the domain, as x increases, f(x) decreases. This means the function exhibits decreasing behaviour.

Symmetry: It is clear to see the graph of f(x) has no symmetry.

Boundedness: Looking at the graph we see it is unbounded above as when we choose negative values, the graph of f(x) explodes upwards exponentially. Choose a value of x, plug it in, next choose (x-1), plug this in and we observe $f(x-1) > f(x)$ for all x in the domain.

The function is however bounded below by 0: no value of x in the domain exists which satisfies $f(x) < 0$ .

Extrema: As far as I can tell, there are no turning points on the curve. (Is this what you mean by extrema?)

Asymptotes: Contrary to the curve's appearance, there are no vertical asymtotes for this curve. The negative-x portion of the curve is just growing so quickly it appears to look like an asymptote. There is a value of f(x) for all x<0. There is however a horizontal asymtote: $y=0$ .