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2 years ago

Given the function f(x) = 8x^2-3x+2 Calculate the following values

Mathematics

1 answer:

chubhunter [2.5K]2 years ago

7 0

$1) \text{ } f(-2)=8(-2)^{2}-3(-2)+2=\boxed{40}\\\\2) \text{ } f(-1)=8(-1)^{2}-3(-1)+2=\boxed{13}\\\\3) \text{ } f(0)=8(0)^{2}-3(0)+2=\boxed{2}\\\\4) \text{ } f(1)=8(1)^{2}-3(1)+2=\boxed{7}\\\\5) \text{ } f(2)=8(2)^{2}-3(2)+2=\boxed{28}$

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a construction worker has rope 9 m long he needs to cut it in pieces that are each 3 /5 m long how many such pieces can he cut w

lapo4ka [179]

Dividing a whole number and an improper fraction seems tricky, but it just has one or two more steps than the normal process. First, convert the whole number "9" into a fraction by giving it a denominator of "1". It should look like 9/1. Now that both numbers are converted into like formats (improper fractions), you should have 9/1 divided by 5/3.

Second, flip 5/3 over into 3/5 - this is the "reciprocal". Now you have 9/1 divided by 3/5. It's just a matter of multiplying across the math sentence. Multiply the numerators (9x3) and the denominators (1 x 5). Your new fraction should be 27/5. This is your answer in the improper fraction format.

You can create other formats depending on the expected answer. For a mixed number, "divide your fraction UP" (27 divided by 5) which gives you 5 and 2/5. This can be further converted into 5.4 if you need your answer in decimal form.

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3 years ago

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Inga [223]

Answer:

See attachment

Step-by-step explanation:

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2 years ago

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Add the equations 4x−4y =-2 and −9x4y=-3

goblinko [34]

Answer:-5x-8y=-5

Step-by-step explanation:

add right sides of equation and even them with result of adding right sides of equation

4x-4y-9x-4y=-2-3

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2 years ago

In a survey of 603 adults, 98 said that they regularly lie to people conducting surveys. Create a 99% confidence interval for th

marysya [2.9K]

Answer:

The population proportion is estimated to be with 99% confidence within the interval (0.1238, 0.2012).

Step-by-step explanation:

The formula for estimating the population proportion by a confidence interval is given by:

$\hat{p}\pm z_{\alpha /2}\times\sqrt{\frac{\hat{p}\times(1-\hat{p})}{n}}$

Where:

$\hat{p}$ is the sample's proportion of success, which in this case is the people that regularly lie during surveys,

$z_{\alpha /2}$ is the critical value needed to find the tails of distribution related to the confidence level,

$n$ is the sample's size.

<u>First</u> we compute the $\hat{p}$ value:

$\hat{p}=\frac{successes}{n}=\frac{98}{603}=0.1625$

<u>Next</u> we find the z-score at any z-distribution table or app (in this case i've used StatKey):

$z_{\alpha /2}=2.576$

Now we can replace in the formula with the obtained values to compute the confidence interval:

$\hat{p}\pm z_{\alpha /2}\times\sqrt{\frac{\hat{p}\times(1-\hat{p})}{n}}=0.1625\pm 2.576\times\sqrt{\frac{0.1625\times(1-0.1625)}{603}}=(0.1238, 0.2012)$

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3 years ago

9( 2k + 3 ) + 2 = 11 ( k- y )

Mashcka [7]

9(2k+3)+2=11 (k-y)
k=-11/7 y+ -29/7

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3 years ago

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