Question

The rectangle below has an area of x^2-7x+10square meters and a width of x - 5 meters.

Answer 1

The area of a rectangle is:

$\sf A=lw$

Plug in what we know:

$\sf x^2-7x+10=l(x-5)$

Factor the left side:

$\sf (x-2)(x-5)=l(x-5)$

Divide (x - 5) to both sides:

$\sf l=\boxed{\sf x-2}$

So the length is x - 2 meters.