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o-na [289]
2 years ago
12

Hello I need help on this math questionBRAINLIEST For the fastest correct answer​

Mathematics
1 answer:
Stells [14]2 years ago
4 0

Answer:

LA: 37.68 in squared

TSA: 94.2 in squared

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The bases of the trapezoid are 6 and 10. The height is 4. Find the area.
kari74 [83]
<h2>Answer:</h2>

b. \ \boxed{32 \sq. \ units}

<h2>Step-by-step explanation:</h2>

A trapezoid is a quadrilateral where at least one pair of opposite sides are parallel. In a trapezoid, the both parallel sides are known as the bases of the trapezoid. So we have two bases, namely, b_{1}\,and\,b_{2}. Also, the height H of the trapezoid is the length between these two bases that's perpendicular to both sides. So the area of a trapezoid in terms of of b_{1},b_{2}\:and\:H is:

A=\frac{(b_{1}\text{+}b_{2})h}{2}

Since:

b_{1}=6, \ b_{2}=10, \ and \ H=4

The area is:

A=\frac{(6\text{+}10)4}{2}=\boxed{32 \sq. \ units}

6 0
3 years ago
I dont understand this
mylen [45]

Answer:

ye me too i cant answer thay

3 0
3 years ago
Select ALL of the following scenarios that can be modeled by the equation 3t−6=17 .
Ne4ueva [31]
The answer is: <span>If you triple the number of miles Karin lives from the school and then add six, you get 17 miles.</span>
4 0
2 years ago
Solve 2cos x+2cos 2x=0 on the interval [0,2pi)
rjkz [21]
2cosx+2cos2x=0 \\ -2sin^2x+2cos^2x+2cosx=0 \\ -2(1-cos^2x)+2cos^2x+2cosx=0 \\ -2+2cos^2x+2cos^2x+2cosx=0 \\ 4cos^2x+2cosx-2=0 \\ t=cos x \\ 4t^2+2t-2=0 \\ \Delta=4+32=36 \\ t_1= \frac{-2-6}{8}=-1 \\ t_2= \frac{-2+6}{8}= \frac{1}{2}  \\ cos x=-1 \lor cos x= \frac{1}{2}    \\ x=-\pi \lor x= \frac{5\pi}{3}
6 0
2 years ago
Read 2 more answers
Can you please help me with this question? thank you!!!
Rufina [12.5K]

Answer:

The top box in the middle, should be 15.

The bottom box on the left should be 1.5

3 0
2 years ago
Read 2 more answers
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