Expand and simplify(2x-3)(3x-5)

Mathematics

2 answers:

Andrews [41]2 years ago

8 0

Answer:

6 $x^{2}$ - 19x + 15

Step-by-step explanation:

(2x - 3) (3x - 5)

2x(3x-5) - 3 (3x-5)

6 $x^{2}$ - 10x - 3 (3x - 5)

6 $x^{2}$ - 10x - 9x + 15

6 $x^{2}$ - 19x + 15

pishuonlain [190]2 years ago

8 0

Answer:

6x² - 19x + 15

Step-by-step explanation:

(2x - 3)(3x - 5)

each term in the second factor is multiplied by each term in the first factor, that is

2x(3x - 5) - 3(3x - 5) ← distribute parenthesis

= 6x² - 10x - 9x + 15 ← collect like terms

= 6x² - 19x + 15

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Please help me !!!

Mashutka [201]

$1)~3x^3+15x^2-2x-10=3x^2(x+5)-2(x+5)=(3x^2-2)(x+5)\\\\
2)~8x^2+12x+2xy+3y=4x(2x+3)+y(2x+3)=(4x+y)(2x+3)\\\\
3)~x^3+2x^2-5x-10=x^2(x+2)-5(x+2)=(x^2-5)(x+2)\\\\
4)~x^4+4x^3+2x+8=x^3(x+4)+2(x+4)=(x^3+2)(x+4)\\\\
5)~6y^2-3y+2yz-z=3y(2y-1)+z(2y-1)=(3y+z)(2y-1)\\\\
6)~x^2y+3x^2-7y^2-21y=x^2(y+3)-7y(y+3)=(x^2-7y)(y+3)\\\\
7)~10x^3-25x^2+4x-10=5x^2(2x-5)+2(2x-5)=\\\\=(5x^2+2)(2x-5)\\\\
8)~2x^2y+6xy-x-3=2xy(x+3)-(x+3)=(2xy-1)(x+3)$