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Alborosie
3 years ago
5

Provide a clear answer while explaining how to do each step to the question below:

Mathematics
1 answer:
likoan [24]3 years ago
7 0

\bf ~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \sqrt[3]{8x^5y^7} \\\\[-0.35em] ~\dotfill\\\\ \sqrt[3]{8x^5y^7}\implies \sqrt[3]{2^3x^5y^7}\implies \left( 2^3x^5y^7 \right)^{\frac{1}{3}}\implies 2^{3\cdot \frac{1}{3}}x^{5\cdot \frac{1}{3}}y^{7\cdot \frac{1}{3}}\implies 2x^{\frac{5}{3}}y^{\frac{7}{3}}

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The prime factorization of a number n can be written as n=pr whose p and r are distinct primes. how many factors does n have not
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It has 3 factors, p, r, and n.
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3 years ago
Turn 1 1/5 to improper fraction
Alex17521 [72]

Answer:

<h2><em><u>6/5</u></em></h2><h2></h2>

Explanation:

Step 1

Multiply the denominator by the whole number

5 × 1 = 5

Step 2

Add the answer from Step 1 to the numerator

5 + 1 = 6

Step 3

Write answer from Step 2 over the denominator

<h2><u>6/5</u></h2><h2><u></u></h2><h2><u>I hope this answer helps you out! Brainliest would be appreciated.</u></h2>
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3 years ago
Heights of men have a bell-shaped distribution, with a mean of 176 cm and a standard deviation of 7 cm. Using the Empirical Rule
Vaselesa [24]

Answer:

a) 68% of the men fall between 169 cm and 183 cm of height.

b) 95% of the men will fall between 162 cm and 190 cm.

c) It is unusual for a man to be more than 197 cm tall.

Step-by-step explanation:

The 68-95-99.5 empirical rule can be used to solve this problem.

This values correspond to the percentage of data that falls within in a band around the mean with two, four and six standard deviations of width.

<em>a) What is the approximate percentage of men between 169 and 183 cm? </em>

To calculate this in an empirical way, we compare the values of this interval with the mean and the standard deviation and can be seen that this interval is one-standard deviation around the mean:

\mu-\sigma=176-7=169\\\mu+\sigma=176+7=183

Empirically, for bell-shaped distributions and approximately normal, it can be said that 68% of the men fall between 169 cm and 183 cm of height.

<em>b) Between which 2 heights would 95% of men fall?</em>

This corresponds to ±2 standard deviations off the mean.

\mu-2\sigma=176-2*7=162\\\\\mu+2\sigma=176+2*7=190

95% of the men will fall between 162 cm and 190 cm.

<em>c) Is it unusual for a man to be more than 197 cm tall?</em>

The number of standard deviations of distance from the mean is

n=(197-176)/7=3

The percentage that lies outside 3 sigmas is 0.5%, so only 0.25% is expected to be 197 cm.

It can be said that is unusual for a man to be more than 197 cm tall.

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3 years ago
I WILL MARK BRAINLIEST FOR THIS!!!!!!!!!!!
igomit [66]

Answer:

She gets a job as a lawyer after graduation.

Step-by-step explanation:

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2 years ago
F is an even function <br> What does a equal?
harina [27]

The function is even, so f(x)=f(-x)

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