Question

the equation 4(x-2)= 1000 is a true equation for a paticular value of x. Explain 2(x-2)=50 is also true for the same value of x

Answer 1

Answer:

Step-by-step explanation:

Comment

I find the wording a bit confusing. Does the question mean that the laws of algebra determine what single vale of x will make the right side = the left side in both equations?

I think that's the way I will interpret it.

The easiest way to solve both of them is to divide by 4 on both sides of the top equation and divide by 2 on the bottom equation.

Solution

Top equation

4(x - 2) = 1000                                 Divide by 4

4(x-2 )/ 4 = 1000/4          

(x - 2)  = 250                                    Remove the brackets

x - 2 = 250                                       Add 2 to both sides

x - 2 + 2 = 250 + 2                           Combine

x = 252

Bottom equation

2(x - 2) = 50                                      Divide by 2

2(x - 2)/2 = 50/2

(x - 2) = 25                                        Remove the brackets

x - 2 = 25                                          Add 2 to both sides

x - 2 + 2 = 25 + 2                              Combine

x = 27

Conclusion

If the equations are structured the same way but have different numbers then the answers will be unique.