X+y=62 ; x-y=12 Solve for x in one equation and plug that value into the other equation. ===> x=12+y ; 12+y+y=62 Subtract 12 to both sides (2y=50), then divide by 2 to find y (y=25). Now, plug 25 as y into x=12+y, getting x=37. Your two numbers are 37 and 25.
Answer:
3
Step-by-step explanation:
Here is the equation:

Since 4 is next to the parentheses, you have to multiply everything in the parentheses by 4.
First multiply 3x by 4:

Now multiply 2 by 4:

Now add them together:

Your answer is <u>12x + 8</u>
There are two Right angled triangles in the given figure, with two missing sides, let's name the other missing side be " y "
According to Pythagoras theorem,

note :
- p = perpendicular / opposite side
- b = base / adjacent side
- h = hypotenuse
let's solve for " y² " first ( square of other missing side )



now let's solve for " x " , by using pythagorous theorem




Approximate :

