Answer:
- length: 5.7 yd
- width: 1.7 yd
Step-by-step explanation:
Let w represent the width of the carpet. Then the length is w+4 and the area is ...
w(w +4) = 10
w² +4w = 10 . . . . . eliminate parentheses
w² +4w +4 = 14 . . . . . . add the square of half the w-coefficient to complete the square
(w +2)² = 14 . . . . . . . . . rewrite as a square
w +2 = √14 . . . . . . . . . take the square root
2 = -2 +√14 ≈ 1.7 . . . . yards (width)
Then the length is 4 more yards than this, so is ...
length = 1.7 +4 = 5.7 . . . yards
The length and width are 5.7 and 1.7 yards, respectively.
_____
In the attached graph, we let x represent the length. As you can see, the magnitudes of the two zeros are width and length.
Answer:
the line represents the average slope in which the dots line up. in other words, it shows where most of the options/solutions are on the plot
Step-by-step explanation:
nice pfp
The van is traveling about 55.9 miles per hour.
Hello from MrBillDoesMath!
Answer:
l = 12 feet, w = 5.5
Discussion:
Let w be the width of the pen and "l" the length. From the problem statement
l = w + 6.5 and the perimeter, P, of the fence -= 35.
Now the perimeter of the rectangle is given by the formula
P = 2l + 2w.
In our case, P = 35 and l = w + 6.5 so the equation becomes:
35 = 2(w+6.5) + 2w =>
35 = 2w + 13 + 2w =>
35 = 4w + 13 => (subtract 13 from both sides)
35-13 = 4w =>
22 = 4w =>
w = 22/4 = 5.5 feet
As, l = w + 6.5, l = 5.5 + 6.5 = 12 feet
Thank you,
MrB
Surface area is just the area of all these 4 triangles plus the rectangle.
First we can find the area of the rectangle.

Half of the length is 28 cm, so the full length must be 28 * 2 = 56 cm.


The base for the left and right triangles are 27. The heights would be the net length minus half the length of the rectangle:

Calculate the area:



We have two of these triangles.

Now do the other two pair of triangles. The bases for them are 28 + 28 = 56 cm. The heights would be the net width minus the width of the rectangle:

Now find the area:



We have two of these triangles.

Add all the areas together: