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Nuetrik [128]
2 years ago
12

Find the value of x to the nearest tenth.

Mathematics
2 answers:
Tresset [83]2 years ago
8 0
X/32=tan54
X=44
But since it is to nearest tenth it is 44.0
Blababa [14]2 years ago
5 0

Answer:

59.3

Step-by-step explanation:

tanx=54/32

tanx=59.3

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Five swimmers entered a competition. Four of the swimmers have had their turns. Their scores are 10.8s, 10.75s, 10.79s and 10.81
Shalnov [3]

Answer:

10.74s or faster (lower)

Step-by-step explanation:

The lowest time out of all of them is 10.75, so to all the 5th swimmer needs to do to win is to undercut the swimmer who got 10.75s by a 100th of a second. i.e 10.74s or faster (lower) would win.

6 0
3 years ago
Help!!!!!!! Meeee plead I’ve already out this question down but nobody answers it:(
lorasvet [3.4K]

Answer:

1. Y = 6

2. Y = 8

3. Y = 1

4. Y = 3

Step-by-step explanation:

1. Y = -(-1) + 5 = 1 + 5 = 6

2. Y = -(-3) + 5 = 3 + 5 = 8

3. Y = -4 + 5 = 1

4. Y = -2 + 5 = 3

Hope this helps you!

3 0
3 years ago
Read 2 more answers
Becky is rolling a number cube with the number 1 through 6 what is the probability she will roll a 4 or 5
ryzh [129]
1/6 since there are 6 sides, therefore, there is a 1/6 chance that any number will be rolled
8 0
3 years ago
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Plutonium–238 has a yearly decay constant of 7.9 × 10-3. If an original sample has a mass of 15 grams, how long will it take to
eduard
The answer is 28 years

At = A0 * e^(-k * t)
At = 12 g
A0 = 15 g
k = 7.9 × 10^-3 = 0.0079 
t = ?

12 = 15 * e^(-0.0079 * t)
12/15 = e^(-0.0079 * t)
0.8 = e^(-0.0079 * t)

Logarithm both sides (because ln(e) = 1:
ln(0.8) = ln(e^(-0.0079 * t))
ln(0.8) = (-0.0079 * t) * ln(e)
-0.223 = -0.0079 * t
t = -0.223 / -0.0079
t = 28.23
t ≈ 28 years
8 0
3 years ago
(10.02)
melisa1 [442]

Answer:

sin O=\dfrac{3\sqrt{13}}{13}\\cos O=\dfrac{2\sqrt{13}}{13}\\tan O=\dfrac{3}{2}

Step-by-step explanation:

If the point (2,3) is on the terminal side of an angle in standard position.

Adjacent of O, x=2,

Opposite of O, y=3

Next, we determine the hypotenuse, r using Pythagoras Theorem.

Hypotenuse =\sqrt{Opposite^2+Adjacent^2} \\r=\sqrt{3^2+2^2} \\r=\sqrt{13}

Therefore:

sin O=\dfrac{Opposite}{Hypotenuse} \\sin O=\dfrac{3}{\sqrt{13}} \\$Rationalizing\\sin O=\dfrac{3\sqrt{13}}{13}

cos O=\dfrac{Adjacent}{Hypotenuse} \\cos O=\dfrac{2}{\sqrt{13}} \\$Rationalizing\\cos O=\dfrac{2\sqrt{13}}{13}

Tan O=\dfrac{Opposite}{Adjacent} \\tan O=\dfrac{3}{2}

4 0
3 years ago
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