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Reika [66]
3 years ago
13

4(x - 2) = 2x + 3(x - 5)

Mathematics
1 answer:
yaroslaw [1]3 years ago
8 0

Answer:

x=7

Step-by-step explanation:

  1. 4(x-2) = 2x+3(x-5)
  2. 4x-8 = 2x+3x-15
  3. 4x-8 = 5x -15
  4. -x = -7
  5. x = 7

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What is the area?? Please help
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Answer:

<h3>324 ft²</h3>

Step-by-step explanation:

We have the triangle and the rectangle.

The formula of an area of a triangle:

A_{\triangle}=\dfrac{1}{2}bh

b - base

h - height

The formula of an area of a rectangle:

A_{\boxed{\ }}=lw

l - length

w - width

We have b = 24 ft, h = 7 ft, l = 24 ft and w = 10 ft.

Substitute:

A_\triangle=\dfrac{1}{2}(24)(7)=(12)(7)=84\ ft^2

A_{\boxed{\ }}=(24)(10)=240\ ft^2

The area of the figure:

A=A_{\triangle}+A_{\boxed{\ }}

Substitute:

A=84+240=324\ ft^2

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3 years ago
7/√10-√3<br> plss faast very urgent​
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▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Here's the solution :

  • \dfrac{7}{ \sqrt{10 }  -  \sqrt{ 3} }

  • \dfrac{7}{ \sqrt{10} -  \sqrt{ 3}  }  \times  \dfrac{ \sqrt{10}  +  \sqrt{3} }{ \sqrt{10}  +  \sqrt{3} }

  • \dfrac{7( \sqrt{10}  +  \sqrt{3} )}{( \sqrt{ 10}) {}^{2} - (  \sqrt{ {3}})^{2}  }

  • \dfrac{7 (\sqrt{10}  +  \sqrt{3}) }{10 - 3}

  • \dfrac{7( \sqrt{10}  +  \sqrt{3} )}{7}

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Someone could tell me how to identify a direct and inverse proportionality? THANKS, IS IMPORTANT​
stiks02 [169]

Answer:

Directly proportional: as one amount increases, another amount increases at the same rate.

Inversely Proportional: when one value decreases at the same rate that the other increases.

Step-by-step explanation:

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3 years ago
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Let f(x)=x^3-x-1
alexira [117]
f(x) = x^3 - x - 1

To find the gradient of the tangent, we must first differentiate the function.

f'(x) = \frac{d}{dx}(x^3 - x - 1) = 3x^2 - 1

The gradient at x = 0 is given by evaluating f'(0).

f'(0) = 3(0)^2 - 1 = -1

The derivative of the function at this point is negative, which tells us <em>the function is decreasing at that point</em>.

The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so

y = -x + c

Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).

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So the point (0, -1) lies on the tangent. Substituting into the tangent equation:

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