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andrezito [222]
1 year ago
5

Solve: 7 x + 2 y = 16; -21 x-6 y = 24 Solve : 7 x + 2 y = 16 ; -21 x - 6 y = 24​

Mathematics
1 answer:
Marat540 [252]1 year ago
7 0

Answer:

No solution

Step-by-step explanation:

<h3>Solving system of linear equations:</h3>

 7x + 2y = 16 ----------------(I)

-21x - 6y = 24 -----------------(II)

\sf \dfrac{a_1}{a_2}=\dfrac{7}{-21}=\dfrac{-1}{3}\\

\sf \dfrac{b_1}{b_2}=\dfrac{2}{-6}=\dfrac{-1}{3}

\sf \dfrac{c_1}{c_2} =\dfrac{16}{24}=\dfrac{2}{3}\\\\ \dfrac{a_1}{a_2}=\dfrac{b_1}{b_2} \neq  \dfrac{c_1}{c_2}

So, the lines are parallel and has no solution

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Find out net profit after tax from the following information:
WARRIOR [948]

Answer:

Net Profit after tax Rs 15,000

Step-by-step explanation:

The computation of the net profit after tax is shown below:

Gross profit Rs. 1,25,000

Less:

Selling and distribution expenses Rs. 21,000

General and administrative expenses Rs. 75,000

Interest on loan Rs. 5,000

Gain on sale of plant Rs. 4,000

Profit before tax Rs 20,000

Less: income tax expense at 25% of Rs 20,000 Rs 5000

Net Profit after tax Rs 15,000

3 0
3 years ago
I need help please, the question is The temperature at 6am is 12 F. During the next twelve hours, the temperature increases 25 F
SIZIF [17.4K]

Answer:

14 degrees

Step-by-step explanation:

12 + 25 - 23 = 14

7 0
3 years ago
Suppose that the total cost of flatiron TVs is given by the function TC(Q) = 500Q + 300 dollars, where Q is the number of TVs pr
Harrizon [31]

The value of TC(10) is 5300 Dollars

Given function is TC(Q) = 500Q +300 dollars

We need to calculate the value for TC (10)

As we know that the equation given is TC(Q) = 500Q + 300 dollars

Q is the number of TVs produced

Therefore, The value of Q is 10 for TC(10)

Substituting the value of Q

in the total cost of flatiron TVs given by function TC(Q) = 500Q + 300 dollars That Q= 100,

TC(10) = 500(10)+300 dollars

∴ TC (10) = 5000+300 dollars

∴ TC (10) = 5300 dollars

Hence the value of TC(10) is 5300 Dollars

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7 0
2 years ago
Please help thank you! will give brainliest!
VashaNatasha [74]

A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).

 

<h3>Calculate the vertices of ΔA'B'C':</h3>

Given that,

ΔABC : A(-6,-7), B(-3,-10), C(-5,2)

(x,y)→(x,y-3)

The vertices are:

  • A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
  • B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
  • C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)

Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).

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7 0
2 years ago
Solve using the quadratic formula 5x^2-4x=2
Alexus [3.1K]

Answer: x= ±(√30) / 5

Step by step:




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