Answer:
Most people found the probability of just stopping at the first light and the probability of just stopping at the second light and added them together. I'm just going to show another valid way to solve this problem. You can solve these kinds of problems whichever way you prefer.
There are three possibilities we need to consider:
Being stopped at both lights
Being stopped at neither light
Being stopped at exactly one light
The sum of the probabilities of all of the events has to be 1 because there is a 100% chance that one of these possibilities has to occur, so the probability of being stopped at exactly one light is 1 minus the probability of being stopped at both lights minus the probability of being stopped at neither.
Because the lights are independent, the probability of being stopped at both lights is just the probability of being stopped at the first light times the probability of being stopped at the second light. (0.4)(0.7) = 0.28
The probability of being stopped at neither is the probability of not being stopped at the first light, which is 1-0.4 or 0.6, times the probability of not being stopped at the second light, which is 1-0.7 or 0.3. (0.6)(0.3) = 0.18
Step-by-step explanation:
Answer:
10 (love biking)
Step-by-step explanation:
The ratio is 2(Skateboarding):5(biking) which, when doubled is; 4(skateboarding):10(biking)
1/2 divide by 3 or 1/[2(3)] which will be equal to 1/6
Answer:
5.75
Step-by-step explanation:
4) 230 ÷ 40 = 5.75
Answer:
Brian has $776 more account in his account than Chris.
Step-by-step explanation:
Compound interest Formula:
= A-P
A= Amount after t years
P= Initial amount
r= Rate of interest
t= Time in year
Given that,
Brian invests $10,000 in an account earning 4% interest, compounded annually for 10 years.
Here P = $10,000 , r= 4%=0.04, t=10 years
The amount in his account after 10 years is
=$14802.44
≈$14802
Five years after Brian's investment,Chris invests $10,000 in an account earning 7% interest, compounded annually for 5 years.
Here P = $10,000 , r= 7%=0.07, t=5 years
The amount in his account after 5 years is
=$14025.51
≈$14026
From the it is cleared that Brian has $(14802-14026)=$776 more account in his account than Chris.
