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3 years ago

15

to train for a race, you plan to run 1 mile the first week and double the number of miles each week for five weeks. How many mil

es will you run for the 5th week. math problem

1 answer:

SashulF [63]3 years ago

3 0

Answer:

16 Miles

Step-by-step explanation:

For every week you simply multiply the number of miles from the previous week by 2, therefore

Week 1: 1

Week 2: 2

Week 3: 4

Week 4: 8

Week 5: 16

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Many utility companies promote energy conservation by offering discount rates to consumers who keep their energy usage below cer

aleksley [76]

Answer:

a. 0.1681 = 16.81% probability that all five qualify for the favorable rate.

b. 0.5283 = 52.83% probability that at least four qualify for the favorable rates

Step-by-step explanation:

For each Puerto Rico resident, there are only two possible outcomes. Either they qualify for discounted rates, or they do not. The probability of a person in the sample qualifying for discounted rates is independent of any other person in the sample. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

70% of the island residents of Puerto Rico have reduced their electricity usage sufficiently to qualify for discounted rates.

This means that $p = 0.7$

Five residential subscribers are randomly selected from San Juan, Puerto Rico

This means that $n = 5$

a. All five qualify for the favorable rate

This is P(X = 5). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 5) = C_{5,5}.(0.7)^{5}.(0.3)^{0} = 0.1681$

0.1681 = 16.81% probability that all five qualify for the favorable rate.

b. At least four qualify for the favorable rates

This is

$P(X \geq 4) = P(X = 4) + P(X = 5)$

So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{5,4}.(0.7)^{4}.(0.3)^{1} = 0.3602$

$P(X = 5) = C_{5,5}.(0.7)^{5}.(0.3)^{0} = 0.1681$

$P(X \geq 4) = P(X = 4) + P(X = 5) = 0.3602 + 0.1681 = 0.5283$

0.5283 = 52.83% probability that at least four qualify for the favorable rates

5 0

3 years ago

I don’t know which one it is, please help

Deffense [45]

Answer:

c

Step-by-step explanation:

the rectagler is 4 by 8 then the other one is 7 bye 4

answer c

8 0

2 years ago

A delivery truck travels 21 blocks north, 12 blocks east and 26 blocks south. what is its final displacement from the origin? as

irakobra [83]

The displacement is 13 blocks since its last position is 5 blocks south and separated 12 blocks east. We got 13 blocks by using triple phytagoras.

4 0

3 years ago

A house was valued at $238,000. Over several years, the value decreased by 16%, giving the house a new value.

Neko [114]

Answer:

The new value of the house after the 16% decrease would be $199,920.

Step-by-step explanation:

Given that a house was valued at $ 238,000, and over several years, the value decreased by 16%, giving the house a new value, to determine the new value the following calculation must be performed:

238,000 - (238,000 x 0.16) = X

238,000 - 38,080 = X

199.920 = X

Thus, the new value of the house after the 16% decrease would be $ 199,920.

8 0

2 years ago

Select the graph of the solution. Click until the correct graph appears.<br><br> |x| = 3

shtirl [24]

The correct graph is the third one, with the solid dots at -3 and 3.

The bars around x stand for absolute value, which is defined as the distance a number is from 0. We want to know what number or numbers is/are 3 units away from 0 on a number line; the only choices are 3 or -3.

This means we must plot points at -3 and 3. They must be solid points, since these numbers are included in the solution (they are, in fact, the only ones of the solution).

4 0

3 years ago