How many three-letter "words" can be made from 5 letters "FGHIJ" if repetition of letters
1 answer:
The number of ways of the letters FGHIJ can be arranged with repetition and without repetition are 125 and 60 ways respectively.
<h3>How to determine the ways </h3>Formula for permutation with repetition
Formula for permutation without repetition
We have = 5
r = 3
a. If repetition is allowed,
Permutation = = 125 ways
b. If repetition is not allowed,
Permutation =
Permutation =
Permutation =
Permutation = 60 ways
Thus, the number of ways of the letters FGHIJ can be arranged with repetition and without repetition are 125 and 60 ways respectively.
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Answer:
Step-by-step explanation:
Let's factor then solve to find the complex solutions.
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
Equations that are never true:
This equation has no solution.
A non-zero constant never equals zero.
<u><em>Therefore your answer is </em></u>
Answer:
B
Step-by-step explanation:
The best - well, only way- is to check a few points.
Namely -1 (unless your eyesight is really poor!), 0, 1, 2, and 3.
Now you can mark all these points in each graph (well, you could if they were on paper and not on a screen) and see which one of the lines passes through all of them. Spoiler alert, it's the B graph.
A represents , B is the one you want, C is
and D looks like