Question

How many three-letter "words" can be made from 5 letters "FGHIJ" if repetition of letters

Answer 1

The number of ways of the letters FGHIJ can be arranged with repetition and without repetition are 125 and 60 ways respectively.

How to determine the ways

Formula for permutation with repetition

$^nPr = n^r$

Formula for permutation without repetition

$^nPr = \frac{n!}{n-r!}$

We have = 5

r = 3

a. If repetition is allowed,

Permutation = $5^3$ = 125 ways

b. If repetition is not allowed,

Permutation = $\frac{5!}{5-3!}$

Permutation = $\frac{5*4*3*2*1}{2*1}$

Permutation = $\frac{120}{2}$

Permutation = 60 ways

Thus, the number of ways of the letters FGHIJ can be arranged with repetition and without repetition are 125 and 60 ways respectively.

Learn more about permutation here:

brainly.com/question/12468032

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