Answer:

Step-by-step explanation:
Step 1: Apply the rule
![\left(-64\right)=-64\\\\=\sqrt[3]{-64}](https://tex.z-dn.net/?f=%5Cleft%28-64%5Cright%29%3D-64%5C%5C%5C%5C%3D%5Csqrt%5B3%5D%7B-64%7D)
Step 2: Apply the radical rule
![\sqrt[3]{-64}=-\sqrt[3]{64}\\\\=-\sqrt[3]{64}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-64%7D%3D-%5Csqrt%5B3%5D%7B64%7D%5C%5C%5C%5C%3D-%5Csqrt%5B3%5D%7B64%7D)
Step 3: Factor the number
![\:64=4^3\\\\=-\sqrt[3]{4^3}](https://tex.z-dn.net/?f=%5C%3A64%3D4%5E3%5C%5C%5C%5C%3D-%5Csqrt%5B3%5D%7B4%5E3%7D)
Step 4: Apply the radical rule
![\sqrt[3]{4^3}=4\\\\=-4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B4%5E3%7D%3D4%5C%5C%5C%5C%3D-4)
Therefore, ![\:\sqrt[3]{\left(\:-\:64\right)}\:=\:-4](https://tex.z-dn.net/?f=%5C%3A%5Csqrt%5B3%5D%7B%5Cleft%28%5C%3A-%5C%3A64%5Cright%29%7D%5C%3A%3D%5C%3A-4)
Answer:
Option 1
Step-by-step explanation:
The angle is a right angle, and Option 1 is the only option with two angles coterminal to positive or negative 90°.
Answer:
- 57
Step-by-step explanation:
The n th term of an arithmetic sequence is
= a + (n - 1)d
where a is the first term and d the common difference
Here a = 13 and d = - 2.5, thus
= 13 + (28 × - 2.5) = 13 - 70 = - 57
If 40% is 8 grams, then 10% is 2 grams. So, in conclusion, a regular hot dog has 20 grams of fat. And a reduced fat hot dog has 12 grams of fat.
Keep in mind that whenever you have a variable inside an expression, you have to think of it as a placeholder, hiding a certain value which we haven't specified yet.
Expressions with variables are a mean to express the generic idea underneath the expression, rather than its particular value.
So, an expression like x-7 represents the idea of subtracting 7 from a particular number. Once you give a specific value to x, the expression will become an actual subtraction between numbers, and you will be able to compute its value.
So, we have several values for x, which are several ways to turn our "abstract" subtraction into an actual, computable subtraction.
If
, the expression becomes
and it evaluates to
.
If
, the expression becomes
and it evaluates to
.
If
, the expression becomes
and it evaluates to
.
If
, the expression becomes
and it evaluates to
.
If
, the expression becomes
and it evaluates to
.