To find the constant variation, solve for only one hour (in this case).
Divide 100 with 2
100/2 = 50/1
Each hour is 50 miles driven, so your constant variation is 50 mph
If f(x)=x+1 and then x became 2, you would have the function f(x)=3. So basically for that function you would be going up three over 1. That function is already g(x)=4x. If X became 2, you would have g(x)=8x. The rate of up 8 and then over one. Because of that, g(x) would be higher
28/100=14/50=7/25 &the second one 2=200/100 so 200/100+65/100=265/100
265/100=53/20
Answer:
2x^2+4x-16
Step-by-step explanation:
The quadratic can be written as
f(x) = a(x-z1)(x-z2) where z1 and z2 are the roots
f(x) = a (x-2)(x- -4)
a is the leading coefficient
f(x) = 2(x-2)(x+4)
= 2(x^2 -2x+4x-8)
= 2(x^2 +2x-8)
= 2x^2 +4x-16
