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Mandarinka [93]
3 years ago
8

What are two solutions of x^2-2x-4=-3+9

Mathematics
1 answer:
Verizon [17]3 years ago
5 0

Answer:

x^2-2x=10

a few more steps...

the answer is 1+the square root of 11

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In a recent year, 31% of all college students were enrolled part-time. If 8.6 million college students were enrolled part-time t
Ronch [10]

Answer:

28 million college students.

Step-by-step explanation:

We can represent all college students as x. This means that all part-time college students are \frac{31}{100}x. Because all part-time college students are also equal to 8.6 million, we have 8,600,000=\frac{31}{100}x. To find the number of total college students, or x, we have to multiply by 100/31 to get rid of the fraction on the other side:

8,600,00\cdot\frac{100}{31}=x

The left side of the equation evaluates as 27,741,935.5. Because we are asked to round to the nearest million, we have to round to 28 million, which is the closest.

5 0
2 years ago
3r2 + 11r + 8<br> Factor completely
crimeas [40]

Answer:

(3r+8)(4+1)

Step-by-step explanation:

5 0
3 years ago
Two cars leave a town at the same time heading in opposite directions. One car is traveling 12 mph faster than the other. After
Katena32 [7]
<span>Find the speed of each car.
Let a be the first car
Let b be the second car
=> a = x miles per hour
=> b = x + 12 miles per hour
=> 2 (x+ x + 12) = 232 miles per hour
=> 2x + 12 = 232
=> 2x + 12 = 116
=> 2x = 116 - 12
=> 2x / 2 = 104 / 2
=> x = 52 (speed of Car A)
=> 52 + 12 = 64 miles per hour (speed of Car B)</span>



4 0
3 years ago
The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00. Assu
m_a_m_a [10]

Answer: 0.0170

Step-by-step explanation:

Given : The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00.

i.e. \mu=23.50

\sigma=5

We assume the distribution of amounts purchased follows the normal distribution.

Sample size : n=50

Let \overline{x} be the sample mean.

Formula : z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

Then, the probability that the sample mean is at least $25.00 will be :-

P(\overline{x}\geq\25.00)=P(\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\geq\dfrac{25-23.50}{\dfrac{5}{\sqrt{50}}})\\\\=P(z\geq2.12)\\\\=1-P(z

Hence, the likelihood the sample mean is at least $25.00= 0.0170

5 0
4 years ago
Find the domain<br><br><img src="https://tex.z-dn.net/?f=y%20%3D%20%20%5Csqrt%7B3x%20%2B%205%7D%20" id="TexFormula1" title="y =
sveticcg [70]
y=\sqrt{3x+5}\\\\The\ domain:\\\\3x+5\geq0\ \ \ |-5\\\\3x\geq-5\ \ \ |:3\\\\x\geq-\dfrac{5}{3}\to x\in\left[-\dfrac{5}{3};\ \infty\right)
6 0
3 years ago
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