Answer:
mu = x√P(x) - £
£ = x√P(x) - xP(x)
Step-by-step explanation:
We have two equations there. Laying them simultaneously, we can derive the formula for "mu" and sigma. Let sigma be "£"
Equation 1
mu = £[xP(x)]
Equation 2
£^2 = x^2 P(x) - (mu)^2
Since we have sigma raised to power 2 (that is sigma square), we find sigma by square rooting the whole equation.
Hence sigma is equal to
[x√P(x) - mu] ...(3)
Since mu = xP(x), we substitute this into equation (3) to get
Sigma = x√P(x) - xP(x)
mu = x√P(x) - £
Answer:
Type 2 error
Step-by-step explanation:
H0 : μ = 261
H0 : μ > 261
By failing to reject H0 ; when the it is false. This means accepting null hypothesis when it is actually FALSE. Then a type 2 error has been committed.
This is different from a type 1 error whereby the null hypothesis is rejected when it is actually TRUE.
Hence, by finding no evidence to reject the null hypothesis during statistical testing when the actual windspeed of an F5 tornado during statistical testing is actually greater than 261 mph.
Because angleCBD＋angleBDC＋angleC＝180
so angleCBD＋angleBDC＝180－angleC＝180－82＝98
because BC＝DC
so angleCBD＝angleBDC
so 2 angleCDB＝98
so angleCDB＝49
so y＝29
by Joy Xu，紫馨雪汐
