Answer:
y = 3x + 1
Step-by-step explanation:
First, find slope:
Then, put the equation into point-slope form using the point (1, 4):
where m is the slope
y - 4 = 3(x - 1)
If you want to put this into slope-intercept form, it would be
The nature of a graph, which has an even degree and a positive leading coefficient will be
1 answer:
The nature of a graph, which has an even degree and a positive leading coefficient will be<u> up left, up right</u> position
<h3 /><h3>What is the nature of the graph of a quadratic equation?</h3>The nature of the graphical representation of a quadratic equation with an even degree and a positive leading coefficient will give a parabola curve.
Given that we have a function f(x) = an even degree and a positive leading coefficient. i.e.
- y = f(x) = 2x²+ 4
The domain of this function varies from -∞ < x < ∞ and the parabolic curve will be positioned on the upward left and upward right x-axis.
Learn more about the graph of a quadratic equation here:
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