All categories

2 years ago

The nature of a graph, which has an even degree and a positive leading coefficient will be

Mathematics

1 answer:

zaharov [31]2 years ago

6 0

The nature of a graph, which has an even degree and a positive leading coefficient will be<u> up left, up right</u> position

<h3 /><h3>What is the nature of the graph of a quadratic equation?</h3>

The nature of the graphical representation of a quadratic equation with an even degree and a positive leading coefficient will give a parabola curve.

Given that we have a function f(x) = an even degree and a positive leading coefficient. i.e.

y = f(x) = 2x²+ 4

The domain of this function varies from -∞ < x < ∞ and the parabolic curve will be positioned on the upward left and upward right x-axis.

Learn more about the graph of a quadratic equation here:

brainly.com/question/9643976

#SPJ1

You might be interested in

Help simplify √10/18

Marina CMI [18]

Answer:

Letter A

Step-by-step explanation:

Hope this helps

8 0

3 years ago

Read 2 more answers

What is the algebraic expression for the area of this house block?

Sidana [21]

Answer:

x² + 27x + 180

Step-by-step explanation:

(12 + x)(15 +x) = 12*15 + 12x + 15x + x² = x² + 27x + 180

4 0

4 years ago

A colony of 900,000 bacteria doubles

shusha [124]

255 hours / 85 hours = 3.

This means that the bacteria will double in size 3 times.

900,000 × 2 = 1,800,000

1,800,000 × 2 = 3,600,000

3,600,000 × 2 = 7,200,000

After 255 hours, the colony of bacteria will be 7,200,000

5 0

3 years ago

Read 2 more answers

A boat is pulled into a dock by a rope attached to the bow of the boat and passing through a pulley on the dock that is 1 m high

Agata [3.3K]

Answer:

dy/dt = 1.02 m/s

Step-by-step explanation:

First of all, let the distance of the dock above the bow of the boat be represented by x.

Also, let the distance of the boat from the dock be represented by y.

Let z represent the length of the rope.

Now, we can use pythagoras theorem to find a relationship between x, y and z since they form a right angle triangle where the vertical part is the dock, the base represents the water and the hypotenuse represents the rope.

Thus;

x² + y² = z²

Using implicit differentiation, we have;

2x(dx/dt) + 2y(dy/dt) = 2z(dz/dt)

We are given that the dock is 1 meter above the bow. Thus, x = 1

Also, the height is not changing and so dx/dt = 0

We are told the dock is 5 feet away from the boat. Thus, y = 5

dy/dt is is the speed we are looking for which is the rate at which the boat is approaching the dock.

We are not given the value of z but we can find it by using pythagoras theorem since we know the dock is 1 meter above the bow and the boat is 5 m away.

Thus;

z = √(1² + 5²)

z = √26

We are told the rope is being pulled in at the rate of 1 m/s. Thus; dz/dt = 1

Plugging all relevant values into the differentiation equation above gives;

2(1)(0) + 2(5)(dy/dt) = 2(√26)(1)

10(dy/dt) = 2√26

Divide both sides by 10 to get:

dy/dt = (√26)/5

dy/dt = 1.02 m/s

5 0

3 years ago

11 divided by 1/3 (fraction form)

Montano1993 [528]

11 / 1/3
11 * 3/1
33/1

Fraction Form: 33/1
Simplified Form: 33

3 0

3 years ago

Read 2 more answers