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VLD [36.1K]
2 years ago
14

- 12 ÷ (-4) How do I solve this? ​

Mathematics
2 answers:
jonny [76]2 years ago
3 0
Two negatives make a positive so that is going to produce a positive number so -12÷-4 you just do normal division like always and it equals a great positive 3

murzikaleks [220]2 years ago
3 0

Step-by-step explanation:

We're going to be diving -12 by -4.

<u>What do we need to know?</u>

Integer Rule - when 2 negative numbers multiply or divide, the product/quotient is positive.

<u>Solve using the integer rule:</u>

<u />-12 \div -4 =3 is the same as 12 \div 4 = 3

3 is your quotient.

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#6) Beth saved a total of $30 per month for her first car. Beth saved
babymother [125]

Answer:

Domain = 0≤m≤20 for mEZ+

Range = $100≤A≤$700 for all values of m

Step-by-step explanation:

Initial amount in the account = $100

Amount saved by beth monthly = $30

Amount in the bank after X month = $100+$30X where X is the number of months beth intend to save up to.

The amount in her bank in her first month = $100+$30(1)

= $100+$30

= $130

Amount saved in the second month will be when X = 2

= $100+$30(2)

= $100+$60

= $160

The amount in the bank will keep increasing by $30 monthly until the 20month.

The amount he will have in her bank in the 20th month will be at when X = 20

= $100+30X

= $100+30(20)

= $100+$600

= $700

This means that her money will be $130 in the first month and will keep increasing until it reaches $700 in the 20th month.

The DOMAIN will be the interval of the time she used in saving. Since she saved for 20months, the domain will be expressed as 0≤m≤20 for mEZ+ where m is the number of month she uses to save.

The Range will represent the amount she saved within the specified time and will be expressed as $100≤A≤$700 for all values of m.

Where $100 is the amount in the account initially and $700 is the amount in the account after 20 months.

3 0
2 years ago
What is the solution to the following system ?
zvonat [6]

3x+3y+6z=9
x+3y+2z=5
3x+12y+12z=18


Step 1: use Eq 2 to solve for x
x+3y+2z=5
x= -3y-2z+5
Step 2: Solve for y unsing Eq 1
3x+3y+6z=9
3y= -3x-6z+9
y= -x-2z+3

Step 3: plug in x= -3y-2z+5 to solve for the value of y
y=-x-2z+3
y= (-1)(-3y -2z +5) - 2z+3
y= 3y+2z-5- 2z+3
-2y= -2
y=1

Step 4: plug y= 1 into the x= equation 
x= -3y-2z+5
x= -3(1)-2z+5
x= -2z+2
Step 5:Plug y= 1 and x= -2z+2 into the 3rd equation to solve for z
3x+12y+12z=18
12z= -3(-2z+2)-12(1)+ 18
12z= 6z - 6 - 12 +18
6z= -18+18
6z=0
z=0

Step 6: Plug z in to solve for x
x=-2z+2
x= (-2)(0)+2
x= 2

ANSWER:
x,y,z = 2,1,0
answer choice C

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=5%20%2B1" id="TexFormula1" title="5 +1" alt="5 +1" align="absmiddle" class="latex-formula"> x
soldi70 [24.7K]

Answer:

60

Step-by-step explanation:

Put in Parentheses.

(5 + 1) x 10 =

Solve numbers inside parentheses.

5 + 1 = 6

Now we have 6 x 10.

6 x 10 = 60

8 0
2 years ago
There are 2 rows of 8 chairs use the distributive property to solve
vitfil [10]
2(8) 2×8 =16 that is how u do it
3 0
2 years ago
Read 2 more answers
HELP PLEASE!!!!!!!!!!!!!!!!!!!
baherus [9]
The answer is the first 1, 3,929. Because you would have to multiply 0.86 to the 11th power, then multiply that by 20646.
8 0
3 years ago
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