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MAXImum [283]
2 years ago
12

20. Sofia paid $11.80 for a pen, a marker, and a binder. The marker cost $0.80 more than the pen. The binder cost 4 times as muc

h as the marker. What was the cost of the pen?
Mathematics
2 answers:
7nadin3 [17]2 years ago
7 0

Answer:

$1.30

Step-by-step explanation:

Let x = the cost of the pencil

Let x + .80 = the cost of the pen

Let 4(x + .80) = the cost of the binder

x + x + .80 + 4(x + .80) = 11.80

2x + .80 + 4x + 3.20 = 11.80

6x + 4.00 = 11.80

6x = 7.80

x = $1.30

x + .80 = $2.10

4(x + .80) = $8.40

svp [43]2 years ago
6 0
$1.30
Just did the problem and got it correct!
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2d-5=17

2d=17+5

2d=22
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d=11
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3 years ago
Solve the system by substitution.<br> y = -9x<br> y = 2x + 33
Gwar [14]

Answer:

y =  - 9x \\ theny = 2x + 33 \\  - 9x = 2x + 33 \\  - 9x - 2x = 33 \\  - 11x = 33 \\ x =  \frac{ - 33}{11}  =  - 3 \\ x =  - 3 \\then\\ y=-9×-3=21\\ thank \: you

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3 years ago
PLEASE HELP! I'll give 5 out of 5 stars, give thanks, and give as many points as I can.
Liula [17]

Answer:

\boxed{\boxed{x=\dfrac{\pi}{3}\ \vee\ x=\pi\ \vee\ x=\dfrac{5\pi}{3}}}

Step-by-step explanation:

\cos(3x)=-1\iff3x=\pi+2k\pi\qquad k\in\mathbb{Z}\\\\\text{divide both sides by 3}\\\\x=\dfrac{\pi}{3}+\dfrac{2k\pi}{3}\\\\x\in[0,\ 2\pi)

\text{for}\ k=0\to x=\dfrac{\pi}{3}+\dfrac{2(0)\pi}{3}=\dfrac{\pi}{3}+0=\boxed{\dfrac{\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=1\to x=\dfrac{\pi}{3}+\dfrac{2(1)\pi}{3}=\dfrac{\pi}{3}+\dfrac{2\pi}{3}=\dfrac{3\pi}{3}=\boxed{\pi}\in[0,\ 2\pi)\\\\\text{for}\ k=2\to x=\dfrac{\pi}{3}+\dfrac{2(2)\pi}{3}=\dfrac{\pi}{3}+\dfrac{4\pi}{3}=\boxed{\dfrac{5\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=3\to x=\dfrac{\pi}{3}+\dfrac{2(3)\pi}{3}=\dfrac{\pi}{3}+\dfrac{6\pi}{3}=\dfrac{7\pi}{3}\notin[0,\ 2\po)

7 0
4 years ago
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Factor 26r3s + 52r5 – 39r2s4.
algol [13]

Answer:

13r²(2rs + 4r³ - 3s⁴)

Step-by-step explanation:

In equation 26r³s + 52r⁵ - 39r²s⁴;

The GCF of 26, 52, and 39 = 13

The GCF of r³, r⁵ and r² = r²

The GCF of s, (no "s"), and s⁴ = no "s" (Since one of the number doesn't have "s")

Now we can factor out 13r² from all three expressions;

26r³s + 52r⁵ - 39r²s⁴

=> <em>13r²(2rs) + 13r²(4r³) - 13r²(3s⁴)</em>

To factor it all together;

<u>13r²(2rs + 4r³ - 3s⁴)</u>

Hope this helps!

7 0
3 years ago
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