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3 years ago

Which of these is a correct step in constructing an angle bisector

Mathematics

1 answer:

Anastaziya [24]3 years ago

4 0

Answer:

Use a compass to draw two equal arcs ...

Step-by-step explanation:

The attached diagram shows the construction of an angle bisector. First you draw arc DE, then arcs from D and E with the same radius that cross at F.

So, the step on your list is, "use a compass to draw two equal arcs from the intersection points of a previous arc and the legs."

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Tell whether the angles are adjacent or vertical. Then find the value of x.

Serga [27]

Answer:

Adjacent angles. x = 55

Step-by-step explanation:

Adjacent angles are angles that are right next to each other, sharing one side.

Since that is a right angle (90º):

X + 35 = 90

X + (35-35) = 90 - 35

X = 55

Hope this helps! Have a great day!

3 0

2 years ago

Read 2 more answers

Solve for w. 8(w+2) = 40

AleksAgata [21]

Answer:

w = 3

Step-by-step explanation:

8 • (w + 2) - 40 = 0

Pulling out like terms :

3.1 Pull out like factors :

8w - 24 = 8 • (w - 3)

Equation at the end of step 3 :

8 • (w - 3) = 0

Step 4 :

Equations which are never true :

4.1 Solve : 8 = 0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

4.2 Solve : w-3 = 0

Add 3 to both sides of the equation :

w = 3

One solution was found :

w = 3

Processing ends successfully

plz mark me as brainliest :)

7 0

2 years ago

Helppp!! Instructions: Find the missing side. Round your answer to the nearest tenth.

natita [175]

Answer:

x ≈ 14.4

Step-by-step explanation:

using the cosine ratio in the right triangle

cos59° = $\frac{adjacent}{hypotenuse}$ = $\frac{x}{28}$ ( multiply both sides by 28 )

28 × cos59° , then

x ≈ 14.4 ( to the nearest tenth )

4 0

1 year ago

11/ 42 Marks

amm1812

Answer:

(a)x=128 degrees

(b) $\angle APD\neq 116^\circ$

Step-by-step explanation:

$\angle ABD+\angle CBD =180^\circ$ (Linear Postulate)\\\angle ABD+116^\circ =180^\circ\\\angle ABD=180^\circ-116^\circ\\\angle ABD=64^\circ$

(a) Now:

$\angle AOD=2 \times \angle ABD$ (Angle at the centre is twice the angle at the circumference)\\x=2 \times 64^\circ\\x=128^\circ$

(b)

$\angle APD=2 \times \angle ABD$ (Inscribed Angle Theorem)\\\angle APD=2 \times 64^\circ\\ \angle APD=128^\circ$

$\angle APD\neq 116^\circ$

7 0

2 years ago

Solve the System using elimination. 5x-2y=15 7x+7y=-28

steposvetlana [31]

Answer:

x=1 y=-5

Step-by-step explanation:

7(5x-2y=15) ---> 35x-14y=105

2(7x+7y=-28) --> + 14x+14y=-56

49x=49 --->x=1

5(1)-2y=15 ---> 5-2y=15 ---> -2y=10 ---> y=-5

8 0

3 years ago

Which of these is a correct step in constructing an angle bisector​

Which of these is a correct step in constructing an angle bisector