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LenKa [72]
3 years ago
6

Jake made cupcakes for his birthday. He made 13 chocolate and 9 vanilla. What percent of the cupcakes

Mathematics
1 answer:
Leona [35]3 years ago
7 0

Answer:

59 1/11 %

Step-by-step explanation:

13 chocolate and 9 vanilla = 22 total cupcakes

Percent chocolate = 13 chocolate / 22 total

                               =13/22

                               =.59090909

                               =59 1/11 %

                           

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The area of a circle is 25л ft². What is the circumference, in feet? Express your answer in terms of π.​
Ahat [919]

Answer:

C = 10π ft

Step-by-step explanation:

the circumference (C) of a circle is calculated as

C = 2πr ( r is the radius )

to find r use the area formula, that is

A = πr² = 25π ( divide both sides by π )

r² = 25 ( take square root of both sides )

r = \sqrt{25} = 5

then

C = 2π × 5 = 10π ft

4 0
2 years ago
Next consider what happens when two of these functions are composed. Suppose g identifies ng regions of (0, 1)d onto (0, 1)d and
irina [24]

n^{2}fg is regions of f ◦ g(·).

<u>Step-by-step explanation:</u>

When you multiply two functions together, you'll get a third function as the result, and that third function will be the product of the two original functions.

For example, if you multiply f(x) and g(x), their product will be h(x)=f.g(x), or h(x)=f(x)g(x).

Here we have two functions, f identifies n f regions of (0, 1)d onto (0, 1)d which is equivalent to f(x) = n f. And, g identifies n g regions of (0, 1)d onto (0, 1)d which is equivalent to g(x)= n g. Now,

⇒ ( f × g ) (x ) = f(x) × g(x)

⇒( fg )(x) = f(x).g(x)\\( fg )(x) = nf.ng\\(fg)(x) = n^{2}fg

Therefore, n^{2}fg is regions of f ◦ g(·).

8 0
4 years ago
This is for my Iready and I’m super confused the story problem reads ""Lola rode her bike for 7/10 of an hour on Saturday and 3/
goldfiish [28.3K]
First find the decimal values of both fractions:
7/10 is 7 divided by 10 so:
= 0.70

3/5 is 3 divided by 5 so:
= 0.60

60 minutes is one hour (since the question said that Lola rides the bike for 7/10 and 3/5 of an hour)

Now we use these to find how many minutes:
To find 0.70 (or 7/10) of 60 minutes, you multiply 60 x 0.70
= 42 minutes on Saturday

To find 0.60 (or 3/5) of 60 minutes, you multiply 60 x 0.60
= 36 minutes on Sunday

Now to find how much longer she rode her bike on Saturday than Sunday, you subtract the two numbers:
42 - 36
= 6
Therefore, Lola rode her bike for 6 minutes more on Saturday than on Sunday.
6 0
2 years ago
1. Se tiene que 5 kilogramos (kg) de almendra y 4 kg de nuez cuestan $44.00, mientras que 8 kg de almendra y 6 kg de nuez cuesta
Sholpan [36]

Answer:

x = 6.00 $/kg ----> almond

y = 3.5 $/kg ------> nut

Step-by-step explanation:

To find the price per kg of each product you first write the algebraic equations for the given relations:

x : price per kg of almond

y: price per kg of nut

Then, you have:

5x + 4y = 44.00      (1)

8x + 6y = 69.00     (2)

By using substitution you have from (1):

y = (44.00-5x)/(4) = 11.00 - (5/4)x

you replace this expression for y into (2):

8x+6[11.00-(5/4)x] = 69.00

8x+66.00-(15/2)x = 69.00

8x-(15/2)x = 69.00 - 66.00

(1/2)x = 3.00

x = 6.00 $/kg ----> almond

And for nut:

y = 11.00 - (5/4)x = 11.00 - (5/4)(6.00) = 3.5$/kg

y = 3.5 $/kg ------> nut

5 0
3 years ago
Number two please <br> ASAP
miv72 [106K]

The solutions for -5 +2x^{2} = -6x is option 3. x= \frac{-6 \pm \sqrt{36-4 (2)(-5)}}{4} .

Step-by-step explanation:

Step 1:

First, we must bring the equation to the form of ax^{2} +bx +c =0.

So -5 +2x^{2} = -6x becomes 2x^{2} +6x-5=0.

The value of a is the coefficient of the x^{2} term, the value of b is the coefficient of x term and c is the coefficient of the constant term.

Comparing the above equation to ax^{2} +bx +c =0, we get a = 2, b = 6, and c=-5.

We have the formula x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}.

Step 2:

By substituting the known values, we get

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a} =\frac{-6 \pm \sqrt{6^{2}-4 (2)(-5)}}{2 (2)}.

\frac{-6 \pm \sqrt{6^{2}-4 (2)(-5)}}{2 (2)} = \frac{-6 \pm \sqrt{36-4 (2)(-5)}}{4} .

This is the third option.

8 0
4 years ago
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