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Elza [17]
2 years ago
14

Please answer the question down below!! <3

Mathematics
1 answer:
Kryger [21]2 years ago
8 0

Answer:

4 inches

Step-by-step explanation:

In a regular pentagon, all sides are equal in length

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store a sells a 100 oz bottle of cleaner for $12.99 store B sells the same cleaner for $9.49 for a 70 ounce bottle and store sel
solmaris [256]

Answer:

Store C

Step-by-step explanation:

Simply divide the price by the amount to determine which store has the best price efficiency.

A : 12.99 / 100 = .129¢ per oz

B : 9.49 / 70 = .136¢ per oz

C: 10.98 / 90 = .122¢ per oz

Store C has the best price efficiency

3 0
3 years ago
1. Six less than n is less than - 4. how would o write this equation <br>​
posledela

Answer:

n - 6 < -4

Step-by-step explanation:

6 being less than n hints at a subtraction equation, n coming first as the value of the constant is currently unknown. 'Less than -4' hints that -4 is the value on the other side of the inequality, < acting as the 'equal' sign in this sense.

6 0
3 years ago
Read 2 more answers
Find the number of elements in A 1 ∪ A 2 ∪ A 3 if there are 200 elements in A 1 , 1000 in A 2 , and 5, 000 in A 3 if (a) A 1 ⊆ A
lina2011 [118]

Answer:

a. 4600

b. 6200

c. 6193

Step-by-step explanation:

Let n(A) the number of elements in A.

Remember, the number of elements in A_1 \cup A_2 \cup A_3 satisfies

n(A_1 \cup A_2 \cup A_3)=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)

Then,

a) If A_1\subseteq A_2, n(A_1 \cap A_2)=n(A_1)=200, and if A_2\subseteq A_3, n(A_2\cap A_3)=n(A_2)=1000

Since A_1\subseteq A_2\; and \; A_2\subseteq A_3, \; then \; A_1\cap A_2 \cap A_3= A_1

So

n(A_1 \cup A_2 \cup A_3)=\\=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\=200+1000+5000-200-200-1000-200=4600

b) Since the sets are pairwise disjoint

n(A_1 \cup A_2 \cup A_3)=\\n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\200+1000+5000-0-0-0-0=6200

c) Since there are two elements in common to each pair of sets and one element in all three sets, then

n(A_1 \cup A_2 \cup A_3)=\\=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\=200+1000+5000-2-2-2-1=6193

8 0
2 years ago
A student is asked to find a polynomial f(x) of degree four with the zeros 2, -3, 0, and -7. What factors would the student mult
lord [1]

Answer:

(x-2), (x+3),x and (x + 7)

Step-by-step explanation:

Here, the zeros of the polynomial are 2, -3, 0 and -7.

Let’s consider a case of a quadratic equation where x = 5 is a solution. This means that x + 5 is a factor of that quadratic equation.

Now, let’s apply same approach to this polynomial. If x = 2 is a solution, then x -2 is a factor. If x = -3, then, x + 3 is a factor. If x = 0, this means x itself is a solution and lastly, if x = -7 is a solution, that means x + 7 is a factor.

Thus, the factors to multiply together are; (x-2), (x+3),x and (x + 7)

4 0
3 years ago
Find the slope of the line shown on the graph. Please help! :(
Anna [14]

Answer:

It's really easy just remember rise over run.

Step-by-step explanation:

so you rise 3 and run to the right 3

A great tip that helps me determine if it's positive or neagitve is if you go to the left then it's ALWAYS neagtive but if you go to the right then it's ALWAYS postive

7 0
3 years ago
Read 2 more answers
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