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Aneli [31]
3 years ago
11

Solve each triangle for the missing values shown. Show all work necessary. Use exact values

Mathematics
1 answer:
Gelneren [198K]3 years ago
7 0

3)

Cos 60°= \frac{1}{2} = \frac{Adjacent} {Hypotenuse} = \frac{y} {10} \\\\ 2y=10 \\\\ y=5

Now, use Pythagoras theorem to find x

x^2+y^2=10^2 \\\\ \to x^2+5^2=10^2 \\\\ \to x^2+25=100 \\\\ \to x^2 = 100-25 \\\\ \to x^2= 75 \\\\ \to x= \sqrt{75} \\\\ \bf 5 \sqrt{3}

Similarly,

4)

Sin 45°= \frac{1}{\sqrt{2}} = \frac{Opposite} {Hypotenuse} =\frac{2 \sqrt{2}} {a} \\\\ a= 2 \sqrt{2} \times \sqrt{2} \\\\ a=4

Now, use Pythagoras theorem to find b

b^2+(2 \sqrt{2}) ^2=a^2 \\\\ \to b^2+8=4^2 \\\\ \to b^2=16-8  \\\\ \to b^2 = 8\\\\ \to b= \sqrt{8} \\\\ \bf b=2 \sqrt{2}

You can solve all of them in a similar way.

: )

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If AC is parallel to DE, find X
UNO [17]

Answer: x = 50

Concept:

Here, we need to know the idea of alternative interior angles and the angle sum theorem.

<u>Alternative interior angles</u> are angles that are formed inside the two parallel lines, and the values are equal.

The <u>angle sum theorem</u> implies that the sum of interior angles of a triangle is 180°

If you are still confused, please refer to the attachment below or let me know.

Step-by-step explanation:

<u>Given information:</u>

AC ║ DE

∠ABC = 85°

∠A = 135°

<u>Find the value of ∠BAC</u>

∠A + ∠BAC = 180° (Supplementary angle)

(135°) + ∠BAC = 180°

∠BAC = 45°

<u>Find the value of ∠BCA</u>

∠ABC + ∠BAC + ∠BCA = 180° (Angle sum theorem)

(85°) + (45°) + ∠BCA = 180°

∠BCA = 50°

<u>Find the value of x (∠EBC)</u>

∠EBC ≅ ∠BCA (Alternative interior angles)

Since, ∠BCA = 50°

Therefore, ∠EBC = 50°

\Large\boxed{x=50}

Hope this helps!! :)

Please let me know if you have any questions

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Step-by-step explanation:

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