So to start off, we would make 1/3 2/6 so that the bottom number is the same. 2/6 can go in to 5/6 twice so the answer is two bags.
Answer:
0
Step-by-step explanation:
Isolate the variable x. First, distribute 3 to all terms within the parenthesis.
3(2x + 3) = 3(2x) + 3(3) = 6x + 9
6x + 9 = 9
Isolate the variable x. Note the equal sign, what you do to one side, you do to the other. First, subtract 9 from both sides.
6x + 9 (-9) = 9 (-9)
6x = 0
Divide 6 from both sides.
(6x)/6 = (0)/6
x = 0
0 is your answer.
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Answer:
The probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.
Step-by-step explanation:
The three different assembly lines are: A₁, A₂ and A₃.
Denote <em>R</em> as the event that a component needs rework.
It is given that:

Compute the probability that a randomly selected component needs rework as follows:

Compute the probability that a randomly selected component needs rework when it came from line A₁ as follows:

Thus, the probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.