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Sunny_sXe [5.5K]
2 years ago
11

a company promises to release model every month. each model's battery life will be 6% longer than the previous model's. if the c

urrent model's battery is 671.0 minutes, in how many months will the latest model's battery life reach 1,008.9 minutes?
Mathematics
1 answer:
Ratling [72]2 years ago
5 0

The number of months that it will take the latest model's battery life to reach 1,008.9 minutes is; 8 months

<h3>How to solve geometric progression?</h3>

Each month, there is an increase by a factor of 0.06 of the previous months model.

From geometric sequence formula of aₙ = ar^(n - 1),

where;

a is first term

r is common ratio

aₙ is nth term

we have;

1,008.9 = 671 * 1.06^(n - 1)

1008.9/671 = 1.06^(n - 1)

In 1.504 = (n - 1) In 1.06

0.408 = (n - 1) * 0.058

n - 1 = 0.408/0.058

n = 7.03 + 1

n ≈ 8 months

Read more about geometric sequence at; brainly.com/question/24643676

#SPJ1

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A company uses three different assembly lines- A1, A2, and A3- to manufacture a particular component. Of thosemanufactured by li
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The probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

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The three different assembly lines are: A₁, A₂ and A₃.

Denote <em>R</em> as the event that a component needs rework.

It is given that:

P (R|A_{1})=0.05\\P (R|A_{2})=0.08\\P (R|A_{3})=0.10\\P (A_{1})=0.50\\P (A_{2})=0.30\\P (A_{3})=0.20

Compute the probability that a randomly selected component needs rework as follows:

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Compute the probability that a randomly selected component needs rework when it came from line A₁ as follows:

P (A_{1}|R)=\frac{P(R|A_{1})P(A_{1})}{P(R)}=\frac{0.05\times0.50}{0.069}  =0.3623

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