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slamgirl [31]
3 years ago
10

May I have some help please

Mathematics
2 answers:
lubasha [3.4K]3 years ago
3 0

23y+92=30y-130

130+92=30y-23y

222=7y

y=31.7

vazorg [7]3 years ago
3 0
One key step to solving this problem is cross-multiplying.
So if we went through with that, we'd get:
23(y+40) = 10(3y-13)
Now let's substitute:
23y + 920 = 30y - 130
This part is when it gets easy. You just gotta do some rearranging, and you'll be able to find your y:
-7y = -1050
y = 150
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A 2,600 mile flight from los angeles to new york took 5 hours. what was the average rate of speed?
bezimeni [28]

Answer:

2 hours

Step-by-step explanation:

7 0
3 years ago
Here is my math question: Simplify 5x^2-3x-5. I know the answer is 5x^2-13x+3, I don't know how to get to that answer because I
SIZIF [17.4K]
Here you go. I hope you understand. Ask if you don't.

5 0
3 years ago
Given the function defined in the table below, find the average rate of change, in simplest form, of the function over the inter
Igoryamba

Answer:

Average\ Rate = 48

Step-by-step explanation:

Given

See attachment for table

Required

Determine the average rate of change over 5\le x \le 7

Average rate of change is calculated using:

Average\ Rate = \frac{f(b) - f(a)}{b - a}

Where

a \le x\le b

In this case:

a = 5;\ \ \ b = 7

Average\ Rate = \frac{f(b) - f(a)}{b - a}

Average\ Rate = \frac{f(7) - f(5)}{7 - 5}

Average\ Rate = \frac{f(7) - f(5)}{2}

From the table:

f(7) = 108

f(5) = 12

The expression becomes

Average\ Rate = \frac{108 - 12}{2}

Average\ Rate = \frac{96}{2}

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5 0
3 years ago
A random sample of 25 statistics examinations was taken. the average score in the sample was 76 with a standard deviation of 12.
Natali5045456 [20]

Since the sample size is less than 30, therefore we use the t statistic.

Let us define the given variables:

N = sample size = 25

X = average score = 76

s = standard deviation = 12

99% Confidence interval

Degrees of freedom = n – 1 = 24

 

The formula for confidence interval is given as:

CI = X ± t * s / sqrt N

 

using the standard distribution table, the t value for DF = 24 and 99% CI is:

t = 2.492

 

Therefore calculating the CI using the known values:

CI = 76 ± 2.492 * 12 / sqrt 25

CI = 76 ± 5.98

CI = 70.02, 81.98

 

Answer: The average score ranges from 70 to 82.

3 0
3 years ago
4(4x-2) + 1 =16x - 7. Solutions
Talja [164]

Answer:

4(4x - 2) + 1 = 16x - 7

16x - 8 + 1 = 16x - 7

16x - 7 = 16x - 7

-7 = -7

0 = 0

6 0
3 years ago
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