<span>Here let the quadratic equation be ax^2 + bx + c
We know that a=5 from the question.
Since the roots are 6 and 2, the quadratic equation would take the form of a product like (a1x-b1)(a2x-b2).
However, let's assume that a2=1 and b2=6,
Since a=5, a1=5, then 5x-b1=5(x-2). Solving this shows that b1=10
So, the equation is (5x-10)(x-6)</span>
Hello! I would love to help!
Let's start with this part of the equation: "the sum of a number and seven"
Alright. We know that x represents an unknown number. Do you see a part of the equation that could translate to "an unknown number?"
I see "a number." So let's fill X in for "a number.
Alright. So now we have "the sum of x and 7."
Next, let's remember that sum means adding. So we just need to 7 to x
X+7
So, now instead of "the sum of a number and 7" we have x+7.
Alright. Now we just have to do the "twice." When it is asking for "twice", it is asking us to multiply our answer by two. But we need to multiply both x and 7. The best way to do that is to put our "x+7" in parenthesis and put a two outside.
2(x+7)
That's your answer! 2(x+7)
Hope this helped! Comment if you have any questions!
Answer:
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Step-by-step explanation:
Answer:
0.0181 probability of choosing a king and then, without replacement, a face card.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
Probability of choosing a king:
There are four kings on a standard deck of 52 cards, so:
Probability of choosing a face card, considering the previous card was a king.
12 face cards out of 51. So
What is the probability of choosing a king and then, without replacement, a face card?
0.0181 probability of choosing a king and then, without replacement, a face card.
