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1 year ago

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20 POINTS!!! PLEASE HELP

1 answer:

Katena32 [7]1 year ago

3 0

The logarithm of 10 to base 10 is 1

<h3>How to determine the logarithm?</h3>

The given parameters are:

Base = 10

Number = 10

So, the expression is:

$\log_{10}10$

As a general rule;

$\log_{a}a = 1$

The above means that;

When the base and the number are the same, the logarithm is 1

So, we have:

$\log_{10}10 = 1$

Hence, the logarithmic value is 1

Read more about logarithm at:

brainly.com/question/20785664

#SPJ1

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The sum of three numbers is 910. One of the numbers, x, is 60% greater than the sum of the other two numbers. What is the value

KengaRu [80]

Answer:

I don't know I'm sorry I tried to found answers but I couldn't

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2 years ago

Please help! Which box plot represents a set of data that has the greatest mean absolute deviation? (see attached image)

djyliett [7]

Answer:

the 2nd is the answer

Step-by-step explanation:

7 0

3 years ago

Katrina randomly selected 64 students out of her school of 400 students and found that 40 of them want school to start at a late

SashulF [63]

- The sample size is 64.

- The point estimate of the population proportion is 0.625.

-The margin of error is approximately 16%.

6 0

2 years ago

Read 2 more answers

What is the elapsed time from 6:45 am to 3:28 pm

Genrish500 [490]

6:45a to 7:45 = 1 hour

7:45 to 8:45 = 2 hours

8:45 to 9:45 = 3 hours

9:45 to 10:45 = 4 hours

10:45 to 11:45 = 5 hours

11:45 to 12:45 = 6 hours

12:45 to 1:45 = 7 hours

1:45 to 2:45 = 8 hours

2:45 to 3:00 = 8 hours and 15 minutes

then just add the 28 minutes to the 15 minutes

28 + 15 = 43

6:45a to 3:28p = 8 hours and 43 minutes.

Hope this helps.

3 0

3 years ago

ΔCAR has coordinates C (2, 4), A (1, 1), and R (3, 0). A translation maps point C to C' (3, 2). Find the coordinates of A' and R

shutvik [7]

Answer:

$A'= (2,-1)$ and $R'=(4,-2)$ under this translation.

Step-by-step explanation:

A translation in $R^{2}$ is a mapping T from $R^{2}$ to $R^{2}$ defined by $T(x,y) = (x + v_1,y+v_2)$ , where $v=(v_1,v_2)$ is a fixed vector in $R^{2}$ .

From the problem we know that $T(2,4)=(3,2)$ , so we need to find the values $v_1$ and $v_2$ such that $T(2,4) = (2 + v_1,4+v_2)=(3,2)$ , so $3=2 + v_1$ and $4+v_2=2$ , thus $v_1=1$ and $v_2=2$ .

Then $T(x,y) = (x + 1,y-2)$ and

$T(1,1)=(1+1,1-2)=(2,-1)=A'$

$T(3,0)=(3+1,0-2)=(4,-2)=R'$

Therefore $A'= (2,-1)$ and $R'=(4,-2)$ . The triangles CAR and C'Q'R' are shown in the figure below.

7 0

3 years ago