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jolli1 [7]
3 years ago
13

The height of a soccer ball that is kicked from the ground can be approximated by the function:

Mathematics
1 answer:
kumpel [21]3 years ago
3 0
Why do you want me a little bit of
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Find the measure of angle Y
Oksana_A [137]
If all angles are equal it must be an equilateral triangle which means the measure of Y is 60°
6 0
3 years ago
The bending of a bean varies directly as its mas. A beam is bent 20mm by a mass 0f 40kg. how much will the beam bend with a mass
Naddik [55]

Answer:

The beam will bend by 50 mm with a mass of 100kg?

Step-by-step explanation:

The first step in solving the problem of direct variation is setting up the relation mathematically.

We can do this as follows:

The bending of the beam varies directly as its mass.

20  \alpha  40kg

\alpha here is the symbol representing direct variation. To remove this and replace it with an equality sign, we have to introduce a constant of proportionality, k

20 = k \times 40

k = 20 /40 = 0.5

We can now use this to find the distance the beam will bend with a mass of 100kg?

This will be

Bending = 0.5 \times 100 =50mm

There fore, the beam will bend by 50 mm with a mass of 100kg?

6 0
3 years ago
Read 2 more answers
One number is 2 less than a second number. Twice the second number is 5 less than 3 times the first. Find the two numbers.
Evgen [1.6K]

Answer:

9 and 11  

Step-by-step explanation:

First number = x -2

Second number = x

  and   2x = 3(x-2)  - 5

            2x = 3x - 6 - 5

             x = 11

              first number = 11-2 = 9

8 0
2 years ago
Which equation represents the circle described?
faust18 [17]
ANSWER

{(x - 4)}^{2} +  {(y - 3)}^{2}  =   {2}^{2}

EXPLANATION

The equation of the circle with radius r and centre (a,b) is given by


(x - a)^{2}  +  {(x - b)}^{2}  =  {r}^{2}

The radius is

r = 2

We need to determine the center of the circle from the given equation of another circle, which is,


{x}^{2}  +  {y}^{2}  - 8x - 6y + 24 = 0


We complete the square to obtain,


{x}^{2}  - 8x+  {y}^{2}  - 6y + 24 = 0

{x}^{2}  - 8x+  {y}^{2}  - 6y  =  - 24
{x}^{2}  - 8x+  {( - 4)}^{2} +   {y}^{2}  - 6y  +  {( - 3)}^{2}  =  - 24 +  {( - 3)}^{2} +  {( - 4)}^{2}


{(x - 4)}^{2} +  {(y - 3)}^{2}  =  - 24 +  9+  16




{(x - 4)}^{2} +  {(y - 3)}^{2}  =  1


The centre of this circle is (4,3)


Hence the center of the circle whose equation we want to find is also (4,3).


With this center and radius 2, the required equation is,


{(x - 4)}^{2} +  {(y - 3)}^{2}  =   {2}^{2}


Therefore the correct answer is C.

3 0
3 years ago
Read 2 more answers
The answer to eaquivalent fraction 1×2/3×4 answer.
zhuklara [117]
The answer Is 2/12 because if u multiply 1 x2 it is 2 then 3 x4 which is 12
6 0
3 years ago
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